AMC 10 · 2002 · #5
Grade 7 geometry-2d
Pick an answer.
AMC 10 2002 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The whole problem turns on one picture fact: the flat line drawn through both small centers is actually a diameter of the big circle, so Tool #1 (Draw a Diagram) unlocks the size of the big circle by reading the lengths straight off that line. Once the big radius is known, Tool #7 (Identify Subproblems) splits the shaded area into three easy circle-area calculations that combine by subtraction — big circle minus the two small ones.
Read the big diameter off the line
The line through both small centers crosses the big circle end to end, so the big diameter is 3+3+2+2=10.
Lining the small circles up edge to edge stretches them across the full width of the big circle.
7.G.B.4Draw A DiagramGet the big radius
Halve it: the radius is half the diameter, so the big circle has radius 10÷2=5.
Radius is always half the distance straight across.
The radius is always half the distance straight across the circle.
▸ Why?
Every point of the circle sits one radius from the centre, so the widest span is two radii.
▸ Why?
Half is one of two equal shares, so halving that span returns one radius exactly.
Area of the big circle
Use the circle-area formula π r² with r=5: the big circle has area π · 5² = 25π.
Squaring the radius and multiplying by π gives the space a circle covers.
7.G.B.4Identify SubproblemsArea of the two small circles
Same formula for each small circle: π(3)²=9π and π(2)²=4π, so together they cover 13π.
Each white circle is just its own π r².
7.G.B.4Identify SubproblemsSubtract to get the shaded area
Take the covered part away: 25π-13π=(25-13)π=12π, which is choice (E).
Take away the covered part and the leftover π's are the shaded area.
6.EE.A.3Identify SubproblemsLine the two circles up edge to edge and their widths add to the big circle's diameter; then the shaded part is just the big circle's area minus the two smaller ones.
- Read the big diameter off the line
- Get the big radius
- Area of the big circle
- Area of the two small circles
- Subtract to get the shaded area