AMC 10 · 2003 · #10

Grade 6 geometry-3d
net-foldingpolyhedron-netsspatial-visualization complementary-countingphysical-representation ↑ Prerequisites: net-folding
📏 Medium solution 💡 2 insights 📊 Diagram
Problem
A flat shape made of 4 congruent squares joined edge to edge is shown. A fifth congruent square can be attached to the border at any one of 9 marked positions, one at a time, giving 9 different flat shapes. For how many of these 9 shapes can the paper be folded along the square edges into a cube that is missing exactly one face?

Pick an answer.

(A)
2
(B)
3
(C)
4
(D)
5
(E)
6

AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Visualize Spatial Relationships

This is a folding question, so the core skill is Tool #17 (Visualize Spatial Relationships): mentally fold the flat squares up around a cube and watch where each square lands. Tool #1 (Draw a Diagram) keeps the count honest — sketch the base shape and mark the 9 spots so none is missed. The clever move is Tool #16 (Change Focus / Count the Complement): instead of hunting for the positions that work, notice the base 4 squares already fold into 4 good faces, so a new square works unless it collides with a face that is already taken. Counting the few collisions is far easier than checking all 9 successes, so count the failures and subtract from 9.

1STEP 1

Restate the goal as 5 faces

A cube has 6 faces, so missing one leaves 5 — an open box — and 4 base squares plus 1 added square is exactly 5.

6 faces - 1 missing = 5 faces needed
2STEP 2

The 4 base squares already fold cleanly

Folded up, the 4-square strip wraps 4 different faces with no overlap, so four of the five walls already stand.

3STEP 3

A position works unless the new square overlaps

So an added square fails only if it folds onto a face a base square already occupies; land on empty air and the position works.

4STEP 4

Count the failures and subtract

Fold each of the 9 marked spots mentally: 3 overlap a used face and fail, so 9 - 3 = 6 positions work — choice (E).

9 positions - 3 overlaps = 6 → (E)
Answer
6
The base 4 squares already form a working open box, and most of the 9 marked edges point outward into empty space, so we should expect many more successes than failures — a large value like 6 is believable while a tiny value like 2 would be surprising. The only positions that can fail are the ones where the added square folds directly onto a face the base already uses, and exactly 3 of the marked spots do that. So 9-3 = 6 work, matching (E) and not the smaller choices.
💡Key takeaway

A cube missing one face is just five squares folded into an open box; the four given squares already make four walls, so a new square works unless it folds on top of a wall that is already there — and only 3 of the 9 spots do that, leaving 6.

  • Restate the goal as 5 faces
  • The 4 base squares already fold cleanly
  • A position works unless the new square overlaps
  • Count the failures and subtract