AMC 10 · 2003 · #8

Grade 7 probability
factorsdivisor-countprobability-basic systematic-enumeration ↑ Prerequisites: factors
📏 Medium solution 💡 2 insights
Problem
You pick one positive factor of 60 at random, with every factor equally likely. Find the probability that the factor you pick is less than 7.

Pick an answer.

(A)
$\frac{1}{10}$
(B)
$\frac{1}{6}$
(C)
$\frac{1}{4}$
(D)
$\frac{1}{3}$
(E)
$\frac{1}{2}$

AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Make a Systematic List

A probability like this is just a fraction, so the whole job is two counts: how many factors are less than 7 (top) and how many factors there are in all (bottom). Tool #2 (Make a Systematic List) is the safe way to get both without missing or repeating anything — list the factor pairs of 60 in order, and you can read both counts straight off the same list. Tool #7 (Identify Subproblems) keeps the two counts separate so the fraction is assembled cleanly. Tool #16 (Change Focus) gives a fast check: pair each factor d with its partner 60/d, and the pairing shows the small and large factors must split evenly.

1STEP 1

List every factor of 60

Pair the factors so each product is 60: 1×60, 2×30, 3×20, 4×15, 5×12, 6×10. The pairs then cross over, so 60 has 12 factors.

60=1·60=2·30=3·20=4·15=5·12=6·10 → {1,2,3,4,5,6,10,12,15,20,30,60}, 12 factors
2STEP 2

Count the factors below 7

On that list the factors under 7 are 1, 2, 3, 4, 5, 66 of them; 7, 8, 9 are not factors, so the list jumps to 10.

{1,2,3,4,5,6} → 6 factors less than 7
3STEP 3

Write the probability as a fraction

Every factor is equally likely, so the probability is the wanted count over the total count: 6/12.

P=6/12
4STEP 4

Simplify the fraction

Divide top and bottom by 6, so 6/12 reduces to 1/2 — the probability, choice (E).

6/12=1/2 → (E)
Answer
1/2
Exactly half of the 12 factors (6 of them) are less than 7, and half a chance is 1/2 — matching choice (E), and clearly between 0 and 1 as any probability must be. A quick sanity count: the six small factors 1,2,3,4,5,6 sit below 7, and the six large factors 10,12,15,20,30,60 sit above it, a perfect 6-to-6 split.
💡Key takeaway

For a "probability of a factor" question, list every factor in pairs that multiply to the number, count the ones you want and the total, then simplify the fraction.

  • List every factor of 60
  • Count the factors below 7
  • Write the probability as a fraction
  • Simplify the fraction