AMC 10 · 2003 · #4

Grade 5 geometry-2d
area-rectanglesoptimizationdecimal-arithmetic optimization-counting ↑ Prerequisites: area-rectangles
📏 Medium solution 💡 2 insights 📊 Diagram
📘 View easy version →
Problem
A rectangular flower bed is divided into five rectangular regions measuring 7×3, 4×5, 5×3, 6×1, and 2×2 feet. Each region is filled with a single type of flower, one plant per square foot. The five types cost $1, $1.50, $2, $2.50, and $3 per plant, and each type is used in exactly one region. What is the least possible total cost, in dollars?

Pick an answer.

(A)
108
(B)
115
(C)
132
(D)
144
(E)
156

AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Extreme Principle

The total cost is a sum of five products (price × area). To make that sum as small as possible you must decide which price lands on which area, so this is a min/max matching problem — Tool #14 (Extreme Principle). The rule it gives is simple: put the cheapest flower on the biggest region and the most expensive flower on the smallest region. Before you can match, Tool #7 (Identify Subproblems) breaks the bed into its five rectangles so each area can be found on its own, and Tool #8 (Analyze the Units) keeps the bookkeeping honest — square feet become number of plants, and plants times dollars-per-plant give dollars.

1STEP 1

Find the five region areas

Area = length × width, so 7×3, 4×5, 5×3, 6×1, 2×2 give 21, 20, 15, 6, 4 square feet of plants.

21, 20, 15, 6, 4 square feet
2STEP 2

Cheapest flower on the biggest region

Pair prices $1, $1.50, $2, $2.50, $3 with areas 21, 20, 15, 6, 4 in opposite order — cheapest flower on the largest region.

121,1⇔21,1.50⇔20, 215,2⇔15,2.50⇔6, $3⇔4
3STEP 3

Cost of each region

Multiply each pair: 1×21=21, 1.50×20=30, 2×15=30, 2.50×6=15, 3×4=12 dollars — note 1.50×20 is 30, not 3.

21, 30, 30, 15, 12 dollars
4STEP 4

Add up the least total

Adding gives 21+30+30+15+12=108; any other pairing puts a costlier flower on a bigger area, so 108 is least — choice (A).

21+30+30+15+12=108 → (A)
Answer
108
The whole bed holds 21+20+15+6+4=66 plants. If every plant were the cheapest $1 the bill would be $66; if every plant were the priciest $3 it would be $198. The true answer must sit between, and $108 does. It also should beat the average-price estimate: the mean price is $2, giving 2×66=$132, and a smart pairing must come in under that average — $108 does, while the trap choice (C) 132 is exactly the do-nothing average and (D) 144/(E) 156 are worse than average.
💡Key takeaway

To spend the least, put the cheapest flower on the biggest patch and the priciest flower on the smallest patch.

  • Find the five region areas
  • Cheapest flower on the biggest region
  • Cost of each region
  • Add up the least total