AMC 10 · 2003 · #6
Grade 8 geometry-2dPick an answer.
AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The words "horizontal," "height," and "diagonal" describe a shape, so Tool #1 (Draw a Diagram) comes first: drawing the diagonal splits the rectangle into a right triangle whose legs are the length and the height and whose hypotenuse is the 27-inch diagonal. Tool #4 (Introduce a Variable) turns the ratio 4:3 into legs 4x and 3x, so one unknown x describes both sides at once. Tool #5 (Look for a Pattern) spots that legs in the ratio 3:4 make a 3-4-5 right triangle, so the hypotenuse is 5x — no square roots needed, just solve 5x=27.
Draw the diagonal, make a right triangle
Draw the diagonal: it cuts the rectangle into right triangles with legs the length and the height, and the 27-inch diagonal as hypotenuse.
The diagonal of a rectangle is always the hypotenuse of a right triangle whose legs are the two sides.
4.G.A.2Draw A DiagramName the sides with the ratio
Since length : height = 4:3, write the length as 4x and the height as 3x, so one positive unknown x describes both sides.
A ratio 4:3 means both sides grow together, so one multiplier x fixes both.
6.RP.A.3Introduce A VariableUse the 3-4-5 triangle
Legs 3x and 4x are a 3-4-5 triangle scaled by x, since (3x)²+(4x)²=25x²=(5x)², so the hypotenuse gives 5x=27.
Legs in the ratio 3:4 always give a hypotenuse 5 parts long, the classic 3-4-5 triangle.
Legs in the ratio three to four always give a hypotenuse five parts long.
▸ Why?
In a right triangle the square on the long side equals the two squares on the legs added together.
▸ Why?
One scale factor stretches every length together, so the ratio fixes the shape and only the size is free.
Solve for the length
Divide 5x=27 by 5 to get x=5.4, so the horizontal length is 4x=21.6 inches — the nearest choice is 21.5, answer (D).
Once x is known, the length is just four of those equal parts.
6.RP.A.3Introduce A VariableThe diagonal of a 4:3 screen makes a 3-4-5 triangle, so the diagonal is 5 parts — split it into 5 and take 4 of them for the width.
- Draw the diagonal, make a right triangle
- Name the sides with the ratio
- Use the 3-4-5 triangle
- Solve for the length