AMC 10 · 2004 · #15

Grade 4 arithmetic
systems-of-equationslinear-equations-two-var convert-to-algebra ↑ Prerequisites: linear-equations-two-var
📏 Medium solution 💡 2 insights
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Problem
Patty has 20 coins that are a mix of nickels (5 cents) and dimes (10 cents). If every nickel were turned into a dime and every dime were turned into a nickel, the money she has would be 70 cents more than it is now. Find the total value of her coins right now.

Pick an answer.

(A)
$\textdollar 1.15$
(B)
$\textdollar 1.20$
(C)
$\textdollar 1.25$
(D)
$\textdollar 1.30$
(E)
$\textdollar 1.35$

AMC 10 2004 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Change Focus / Count the Complement

Chasing the two unknown counts head-on invites algebra, but the clean move is Tool #16 (Change Focus): stop staring at the totals and watch what one swap does. Turning a nickel into a dime adds exactly 5 cents, and turning a dime into a nickel loses exactly 5 cents. So the whole 70-cent jump is built out of 5-cent steps, and dividing tells you how many more nickels than dimes there are. Tool #8 (Analyze the Units) keeps every quantity in cents so nothing gets misread, and Tool #6 (Guess and Check) lets you confirm the split lands on 20 coins.

1STEP 1

See what one swap does

A nickel is 5 cents and a dime is 10 cents, so swapping any single coin moves the total by exactly 5 cents, up or down.

10-5=5 cents per coin
2STEP 2

Turn the 70-cent jump into a count

The total rose 70 cents in 5-cent steps, so Patty has 14 more nickels than dimes.

70 ÷ 5 = 14 → (nickels) - (dimes) = 14
3STEP 3

Split the 20 coins

Set the 14 extra nickels aside and the other 6 coins split evenly, giving 17 nickels and 3 dimes.

(20-14) ÷ 2 = 3 dimes, 3+14 = 17 nickels
4STEP 4

Add up the value

17 × 5 + 3 × 10 = 85 + 30 = 115 cents, which is $1.15 — choice (A).

17 × 5 + 3 × 10 = 85 + 30 = 115 cents = $ 1.15 (A)
Answer
$ 1.15
Test the swap on the answer. With 17 nickels and 3 dimes the total is 115 cents. After the swap Patty would have 3 nickels and 17 dimes, worth 3 × 5 + 17 × 10 = 15 + 170 = 185 cents. The difference is 185 - 115 = 70 cents, exactly as the problem says, and 17+3 = 20 coins checks out too. The value also lands right on a listed choice, $1.15.
💡Key takeaway

Watch what one swap changes instead of the whole pile: since each swapped coin shifts the total by 5 cents, a 70-cent jump means 14 more nickels than dimes, which forces 17 nickels and 3 dimes worth $1.15.

  • See what one swap does
  • Turn the 70-cent jump into a count
  • Split the 20 coins
  • Add up the value