AMC 10 · 2005 · #3
Grade 5 rate-ratioPick an answer.
AMC 10 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The paint changes one day at a time, so Tool #7 (Identify Subproblems) handles it as two small steps: find what is left after day 1, then find what day 2 removes. Tool #16 (Change Focus / Count the Complement) keeps the eye on what is LEFT rather than what is used — the whole trap of the problem, since the paint USED totals 5/9, which is choice (E). Tool #3 (Eliminate Possibilities) then rules out the copy-cat traps: 1/9 if you wrongly take 1/3 of 1/3, and 1/3 if you stop after day 1.
Paint left after day 1
Write the whole gallon as thirds and take day 1's share away: is left when day 2 begins.
Using one of three equal parts leaves the other two, so two thirds remain.
5.NF.A.1Identify SubproblemsPaint used on day 2
Day 2 takes a third of what is left, not of the whole gallon, and "of" means multiply: .
Taking a fraction "of" another fraction means multiplying the two together.
Taking a fraction of another fraction means multiplying the two together.
▸ Why?
A fraction of a quantity is that quantity cut into equal shares, so a share of a share is a smaller share.
▸ Why?
Scaling twice by two factors scales the whole by their product, whatever the starting amount.
Paint available on day 3
Subtract what day 2 used from what day 2 started with: , choice (D).
What is left plus what is used must fill the whole gallon, so track one and the other follows.
5.NF.A.1Change Focus Count The Complement"A third of what's left" means multiply by the leftover, not the whole — and since the question asks what's still there, track what stays, not what's gone.
- Paint left after day 1
- Paint used on day 2
- Paint available on day 3