AMC 10 · 2006 · #12

Grade 8 algebra
systems-of-equationscoordinate-geometrylinear-equations-two-var convert-to-algebra ↑ Prerequisites: systems-of-equations
📏 Medium solution 💡 2 insights
Problem
Two lines are given by x=(1/4)y+a and y=(1/4)x+b, where a and b are constants, and they cross each other at the point (1,2). Find the value of a+b.

Pick an answer.

(A)
0
(B)
$\frac{3}{4}$
(C)
1
(D)
2
(E)
$\frac{9}{4}$

AMC 10 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Introduce a Variable

The point (1,2) is where the lines meet, which means it sits on each line — so its coordinates must satisfy both equations. Tool #4 (Introduce a Variable) is really about setting up and solving equations for an unknown: here a and b are the unknowns, and substituting x=1, y=2 turns each two-variable line into a one-line equation that hands over a (from the first) and b (from the second). Add them for a+b. Tool #15 (Organize Information in More Ways) offers a slicker route — add the two original equations before substituting so a+b appears together in one step. Tool #3 (Eliminate Possibilities) then confirms the result against the five listed choices.

1STEP 1

Use that the point lies on both lines

The lines meet at (1,2), so that one point sits on both — meaning x=1 and y=2 must satisfy each equation.

(1,2) on both → x=1, y=2 satisfy each equation
2STEP 2

Plug the point into the first line to get a

Put the point into x=(1/4)y+a: 1=(1/4)·2+a=1/2+a, so a=1/2.

1=1/4(2)+a=1/2+a → a=1/2
3STEP 3

Plug the point into the second line to get b

Put the same point into y=(1/4)x+b: 2=(1/4)·1+b=1/4+b, so b=8/4-1/4=7/4.

2=1/4(1)+b=1/4+b → b=7/4
4STEP 4

Add a and b

Match denominators and add: a+b=1/2+7/4=2/4+7/4=9/4, which is choice (E).

a+b=1/2+7/4=2/4+7/4=9/4 → (E)
Answer
9/4
Check the constants back in the lines. First line: 1/4(2)+1/2=1/2+1/2=1=x. Second line: 1/4(1)+7/4=1/4+7/4=8/4=2=y. Both equations hold at (1,2), so a=1/2 and b=7/4 are right, and a+b=9/4. The sum is a little more than 2, which fits it being the largest choice, (E).
💡Key takeaway

An intersection point sits on both lines, so plug its coordinates into each equation — everything else drops out and the unknown constants fall right into your hands.

  • Use that the point lies on both lines
  • Plug the point into the first line to get a
  • Plug the point into the second line to get b
  • Add a and b