AMC 10 · 2006 · #2
Grade 7 algebraPick an answer.
AMC 10 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The expression is one ♠ wrapped around another, so Tool #7 (Identify Subproblems) says: solve the inner operation 4 ♠ 5 first, get a single number, then feed that number into the outer 3 ♠ ( ). Spotting that (x+y)(x-y) is the difference-of-squares pattern x²-y² turns each ♠ into a quick 'square minus square'. Tool #3 (Eliminate Possibilities) guards the main trap: the operation is not associative, so grabbing 3 and 4 first, or swapping which number is x, lands on one of the wrong choices.
Read the rule as difference of squares
Multiply (x+y)(x-y) out: the cross terms +xy and -xy cancel, so every ♠ is just x² - y² — first number squared minus second squared.
A sum times its matching difference always collapses to one square minus the other.
A sum times its matching difference always collapses to one square minus the other.
▸ Why?
The two cross terms are opposites, so they wipe each other out and only the squares survive.
▸ Why?
Each piece of one factor reaches every piece of the other, which is what produces those cross terms.
Do the inner operation first
Inside the parentheses x=4 and y=5, so 4 ♠ 5 = 16 - 25 = -9 — the larger square is the one being taken away.
Squaring the bigger second number makes the difference negative.
6.EE.A.1Identify SubproblemsFeed the result into the outer operation
Now 3 ♠ (-9) with x=3, y=-9: 3² - (-9)² = 9 - 81 = -72, choice (A) — squaring -9 gives +81, not -81.
Take away a much larger square from a small one and you land far below zero.
7.NS.A.1Eliminate PossibilitiesWhen a made-up symbol is defined by a formula, do the operation inside the parentheses first, then plug that number into the outer one — and watch the signs when a square gets subtracted.
- Read the rule as difference of squares
- Do the inner operation first
- Feed the result into the outer operation