AMC 10 · 2006 · #6

Grade 7 geometry-2d
circle-circumferenceperimeterspatial-visualization identify-subproblems ↑ Prerequisites: circle-circumferenceperimeter
📏 Short solution 💡 2 insights 📊 Diagram
Problem
A square has sides of length 2/π. On each side, a semicircular arc is built using that side as its diameter, and the four arcs bulge outward to bound a flower-like region. Find the perimeter of that region.

Pick an answer.

(A)
$\frac{4}{\pi}$
(B)
2
(C)
$\frac{8}{\pi}$
(D)
4
(E)
$\frac{16}{\pi}$

AMC 10 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Identify Subproblems

The perimeter is one curvy loop, but it is built from four identical semicircular arcs. Break the problem into one small piece: find the length of a single arc, then multiply by four. Finding one arc needs the circle circumference formula, which first needs the radius from the given side.

1STEP 1

Side is the diameter

Each semicircle takes a whole side as its diameter, so the diameter is 2/π and the radius is half of it: 1/π.

r = 1/2·2/π = 1/π
2STEP 2

Length of one arc

A semicircular arc is half of 2πr, namely πr, and r = 1/π makes the π cancel, so one arc has length 1.

arc = π r = π·1/π = 1
3STEP 3

Add the four arcs

The boundary is exactly four such arcs, one per side, so the perimeter is 4·1 = 4, choice (D).

P = 4 · 1 = 4
Answer
4
The result 4 is one of the listed choices and is a clean whole number, which fits how the side 2/π was chosen so the π cancels. As a sanity check, four semicircles equal two full circles; two circumferences are 2·(2πr) = 4πr = 4π·(1/π) = 4, the same answer. The straight sides were correctly ignored because they lie inside the region.
💡Key takeaway

When a boundary is made of identical curved pieces, measure one piece and multiply, and a cleverly chosen radius can make the π cancel to a whole number.

  • Side is the diameter
  • Length of one arc
  • Add the four arcs