AMC 10 · 2008 · #2
Grade 6 geometry-2dPick an answer.
AMC 10 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Because only ratios are given, the shape's size is free — so pick a name for the one length everything is compared to. Tool #4 (Introduce a Variable): let the square's side be s and write every other length in terms of s. Tool #1 (Draw a Diagram) makes the two ratios concrete and confirms the square fits inside. Once both areas are in terms of s, the s cancels and Tool #3 (Eliminate Possibilities) confirms the single matching choice.
Draw it and name the side
Sketch it and let the square's side be . The width is twice the side, so the width is .
Naming the smallest length s lets every other length be measured against it.
6.RP.A.1Draw A DiagramUse the second ratio for the length
The length is twice the width, and the width is , so the length is .
A 2:1 ratio just means doubling, so apply it a second time to the width.
6.RP.A.3Introduce A VariableFind both areas
Rectangle area is times , which is ; the square's area is times , which is .
Both areas come from the same s, so their sizes can be compared directly.
4.MD.A.3Introduce A VariableTurn the fraction into a percent
The ratio cancels to , which is 12.5 percent — choice (A).
Because the variable cancels, the percent is fixed no matter how big the square is.
Because the unknown side cancels, the percent is fixed no matter how big the square is.
▸ Why?
Both areas are built from the same length, so scaling it changes them together and the ratio holds.
▸ Why?
A percent is that ratio counted out of a hundred, so a fixed ratio gives a fixed percent.
When a problem gives only ratios, name the smallest length and build the rest from it — the letter cancels at the end, so the width of 2 and length of 4 make 8 squares, and one of them is 12.5%.
- Draw it and name the side
- Use the second ratio for the length
- Find both areas
- Turn the fraction into a percent