AMC 10 · 2008 · #6
Grade 7 rate-ratioPick an answer.
AMC 10 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The segment length is never given, so I name it with a variable. Because each part is the same length, that length appears in both the total distance and the total time, and it cancels. The unit relation distance = rate x time turns each rate into a travel time, and the whole race becomes total distance over total time.
Name the segment length
Let be one segment's length in km; each of the three covers , so the total distance is km.
Give the unknown length a name so you can carry it through and watch it cancel.
6.RP.A.2Introduce A VariableTurn each rate into a time
Time is distance over rate, so the segments take , , and hours.
The slow parts eat up the most time, so time is where the swim really counts.
6.NS.A.1Analyze The UnitsAdd the three times
Over the common denominator 60 the three times add to hours.
Break total time into three pieces, then a common denominator lets them add cleanly.
5.NF.A.1Identify SubproblemsDivide distance by time
Divide by : multiply by the reciprocal, the cancels, leaving km/h.
Because the length is the same everywhere, it divides out and the answer never depended on it.
Because the segment length is the same everywhere, it divides out and the answer never depended on it.
▸ Why?
Each leg's time is its length divided by its speed, so the same length sits above every term.
▸ Why?
A factor common to distance and time scales both together, so it cancels in their ratio.
Round to the closest choice
Since , the nearest choice among 3, 4, 5, 6, 7 is 6, choice (D).
Once you have the exact fraction, pick the listed number nearest to it.
6.NS.A.1Eliminate PossibilitiesAverage speed is total distance over total time, not the average of the speeds, so the slow swim pulls the whole race down toward 6 km/h.
- Name the segment length
- Turn each rate into a time
- Add the three times
- Divide distance by time
- Round to the closest choice