AMC 10 · 2008 · #11
Grade 8 algebraPick an answer.
AMC 10 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The gap between the known term u₃ and the known term u₆ is filled by two hidden terms, u₄ and u₅. Tool #4 (Introduce a Variable) names those two unknowns so we can work with them. Tool #13 (Convert to Algebra) then turns the recurrence into equations: applying the rule once gives a relation among u₃,u₄,u₅, and applying it again gives a relation among u₄,u₅,u₆ — two equations in the two unknowns. Solving that pair pins down u₅. Tool #3 (Eliminate Possibilities) is the safety net: the answer must be one of the five listed values, and the algebra lands on exactly one of them.
Name the hidden terms
Between u₃=9 and u₆=128 sit two unknown terms: let a=u₄ and b=u₅. The value we want is b.
You can't compute the missing terms yet, so give them letters and let the rule tell you what they must be.
6.EE.B.6Introduce A VariableFirst equation from the rule
Put n=3 in the rule: the newest term is u₅, so u₅=2u₄+u₃, which in the new names reads b=2a+9.
Plugging one starting index into the rule turns the abstract recurrence into a concrete equation linking the two unknowns.
8.EE.C.8Convert To AlgebraSecond equation from the rule
Now n=4 makes u₆ the newest term: u₆=2u₅+u₄, and u₆=128 turns that into 128=2b+a.
Sliding the rule one step forward uses the known end value u₆ and gives a second, independent equation.
8.EE.C.8Convert To AlgebraSolve the two equations
Put a=(b-9)/2 into 128=2b+a and double both sides: 256=5b-9, so b=53, choice (B).
Two equations in two unknowns pin down a single value; substituting one into the other collapses it to one linear equation for b.
Two equations in two unknowns pin down a single pair of values.
▸ Why?
Substituting one equation into the other keeps both true while removing one unknown.
▸ Why?
With one unknown left and one equation to satisfy, only one value can survive.
When terms are missing between two you know, name them with letters, write the rule twice to get two equations, and solve.
- Name the hidden terms
- First equation from the rule
- Second equation from the rule
- Solve the two equations