AMC 10 · 2008 · #4
Grade 5 arithmeticPick an answer.
AMC 10 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The $700,000 cap is shared among all 21 players. To hand one player as much as possible, push everyone else to the smallest amount the rules allow. Once the other 20 sit at the floor, whatever is left of the cap belongs to the last player.
Push the others to the minimum
The 21 salaries share one fixed cap, so drop the other 20 players to the league minimum of 15,000 dollars each.
When a total is fixed, one part grows the most when every other part shrinks to its limit.
When a total is fixed, one part grows the most exactly when every other part shrinks to its limit.
▸ Why?
The parts together make the whole, so whatever the others do not take is what is left for one.
▸ Why?
A smaller total for the others means a larger leftover, so pushing them down pushes the one up.
Cost of the other 20 players
Twenty players at the 15,000 minimum cost 20 times 15,000, a floor of 300,000 dollars.
Twenty equal groups of $15,000 is just repeated addition sped up by multiplication.
5.NBT.B.5Analyze The UnitsWhatever is left goes to one player
Take that 300,000 out of the 700,000 cap and 400,000 dollars is left for the one player — choice (C).
The leftover budget after covering everyone else is exactly what one player can claim.
4.NBT.B.4Convert To AlgebraWhen a total is capped, make one share the biggest by shrinking every other share to its minimum.
- Push the others to the minimum
- Cost of the other 20 players
- Whatever is left goes to one player