AMC 10 · 2009 · #1
Grade 4 arithmeticPick an answer.
AMC 10 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The problem links two units: ounces per can and total ounces needed. Track how ounces build up as cans are added, test whole numbers of cans against the 128-ounce target, and take the smallest count that reaches it.
Set the target
Each can adds 12 ounces, so n cans hold 12 times n — and that total must reach at least 128 ounces.
More cans means more ounces, so we just need enough cans to reach 128.
4.OA.A.3Analyze The UnitsTest 10 cans
Try 10 cans: 12 times 10 is 120 ounces, less than 128, so ten cans fall short of a gallon.
Ten is a round guess, but check the real ounces before trusting it.
4.NBT.B.5Guess And CheckTest 11 cans
Add one more can: 12 times 11 is 132 ounces, which clears 128, so eleven cans make a gallon.
One more can adds 12 ounces, pushing the total just past 128.
4.NBT.B.5Guess And CheckPick the smallest that works
Ten falls short and eleven clears the bar, so the fewest cans reaching a gallon is 11 — choice (E).
The smallest whole number of cans that reaches the goal is the one right after it was still short.
The smallest whole number that reaches the goal is the one right after it was still short.
▸ Why?
Each extra can adds the same fixed amount, so the totals climb in even steps.
▸ Why?
Once a total clears the target, every larger count clears it too, so the first one that clears is the smallest.
When you can only buy whole items, work out how many you need and round UP so you have enough.
- Set the target
- Test 10 cans
- Test 11 cans
- Pick the smallest that works