AMC 10 · 2009 · #16
Grade 7 arithmeticPick an answer.
AMC 10 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The distance from a to d is built from three separate jumps, and each jump can point either forward or backward. That is a small, finite set of choices: two directions for each of three jumps, so eight cases in total. The clean move is to write a - d as one signed sum of the three jumps, then list all eight sign patterns without missing or repeating any. Once the list is complete, take absolute values, throw out duplicates, and add what remains.
Chain the gaps together
Rebuild the a-to-d gap from its neighbors: write a - d as (a - b) + (b - c) + (c - d), where b and c cancel in pairs.
Walking a to b to c to d and adding each step lands you exactly at the a-to-d gap.
6.EE.B.6Introduce A VariableTurn each absolute value into a sign choice
Absolute value fixes size, not direction, so a - b is ±2, b - c is ±3, c - d is ±4, and the chain gives a - d = ±2 ±3 ±4.
Absolute value tells you how far, not which way, so each gap gets a free choice of sign.
6.NS.C.7Introduce A VariableList all eight sign patterns
Three independent sign choices make 2 x 2 x 2 = 8 cases, and running them in order gives a - d = 9, 1, 3, -5, 5, -3, -1, -9.
Two directions for each of three jumps gives a tidy list of eight signed totals.
Two directions for each of three jumps gives a tidy list of eight signed totals.
▸ Why?
Each jump's direction is chosen without regard to the others, so the counts multiply.
▸ Why?
The eight sign patterns never overlap, so listing them covers every possibility exactly once.
Take absolute values and drop duplicates
Sizes pair up as 9, 1, 3, 5, 5, 3, 1, 9, so the distinct ones are 1, 3, 5, 9 and their sum is 18.
Flipping every sign flips the total's sign but not its size, so distinct sizes come in mirror pairs.
7.NS.A.3Eliminate PossibilitiesWhen distances chain together, each hop can go two ways, so list every sign pattern, take absolute values, and add only the different sizes.
- Chain the gaps together
- Turn each absolute value into a sign choice
- List all eight sign patterns
- Take absolute values and drop duplicates