AMC 10 · 2009 · #19

Grade 5 counting
complementary-countingdigit-countingfraction-arithmetic identify-subproblems ↑ Prerequisites: complementary-counting
📏 Medium solution 💡 2 insights
📘 View easy version →
Problem
A 12-hour digital clock shows the hour and minute, but every time a digit should be a 1 it shows a 9 instead — for example, 1:16 is displayed as 9:96. Over a full day, find the fraction of the time the clock happens to display the correct time.

Pick an answer.

(A)
$\ \frac 12$
(B)
$\ \frac 58$
(C)
$\ \frac 34$
(D)
$\ \frac 56$
(E)
$\ \frac {9}{10}$

AMC 10 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Identify Subproblems

The display has two independent parts: the hour and the minute. A time is correct only when the hour is correct AND the minute is correct, and the set of correct minutes is the same in every hour. So split the problem: find the fraction of hours with no 1, find the fraction of minutes with no 1, then multiply the two fractions.

1STEP 1

Reframe: correct means no digit is 1

The clock spoils only the digit 1, so the display is right exactly when not a single digit in it is a 1.

display correct ⇔ no digit equals 1
2STEP 2

Count the correct hours

Hours 1, 10, 11, 12 contain a 1, so only 2 through 9 work: 8 good hours out of 12, a fraction of 23\frac{2}{3}.

good hours = {2,3,4,5,6,7,8,9} → 8/12 = 2/3
3STEP 3

Count the correct minutes

Tens digit 0,2,3,4,5 (5 ways) times ones digit 0,2,…,9 (9 ways) gives 45 good minutes out of 60, a fraction of 34\frac{3}{4}.

5 × 9 = 45 good minutes → 45/60 = 3/4
4STEP 4

Combine the two subproblems

Hour and minute must both be good, and the same 34\frac{3}{4} sits inside every hour, so 23×34=\frac{2}{3}\times\frac{3}{4}= 12\frac{1}{2} — choice (A).

2/3 × 3/4 = 6/12 = 1/2
Answer
1/2
Sanity-check with raw counts: there are 12 × 60 = 720 possible times, and 8 × 45 = 360 of them have no 1. That is exactly 360720=\frac{360}{720}= 12\frac{1}{2}, matching the multiplied fractions. Half is also believable: a 1 is a fairly common digit, so it is reasonable that it spoils about half of all readings.
💡Key takeaway

Split a two-part display into its parts, find the fraction right in each part, then multiply the fractions to get the fraction right overall.

  • Reframe: correct means no digit is 1
  • Count the correct hours
  • Count the correct minutes
  • Combine the two subproblems