AMC 10 · 2010 · #5
Grade 7 geometry-2dPick an answer.
AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The circumference and the area of a circle are not directly linked, but both are built from the same radius r. So name that radius with a letter (Tool #4, Introduce a Variable). The given circumference is the finished output of the formula C = 2π r; run that formula in reverse to recover r (Tool #11, Work Backwards). That splits the task into two clean subproblems (Tool #7): first find r from the circumference, then feed r into the area formula. Solving in this order means no guessing among the five choices.
Name the radius
Let r be the radius. The circumference formula C = 2π r must equal the given 24π.
Every circle fact rides on its radius, so pin the radius down with a letter first.
7.G.B.4Introduce A VariableWork back to the radius
Divide both sides of 2π r = 24π by 2π: the π cancels and 24 ÷ 2 gives r = 12.
Dividing by the same factor on both sides peels the radius out of the circumference formula.
Dividing by the same factor on both sides peels the radius out of the circumference rule.
▸ Why?
A circle's edge is two pi times its radius, so the radius sits inside as a plain factor.
▸ Why?
Dividing both sides of a true equation by the same nonzero number keeps it true.
Compute the area
Put r = 12 into A = π r²: 12² = 144, so A = 144π, and matching kπ gives k = 144.
Once the radius is known, the area is a single plug-in, and squaring 12 makes the number jump.
7.G.B.4Identify SubproblemsBoth the circumference and the area come from the radius, so back the radius out of the circumference first, then square it in the area formula to get k = 144.
- Name the radius
- Work back to the radius
- Compute the area