AMC 10 · 2010 · #10
Grade 7 rate-ratioPick an answer.
AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Two unknown time chunks share one total time and one total distance, so Tool #4 (Introduce a Variable) is the natural fit: name the rain time, write the sun time as "what's left," and turn the distance fact into one equation. Tool #8 (Analyze the Units) keeps the arithmetic honest — speeds are per hour but the answer is wanted in minutes, so units must be converted at the start and again at the end.
Match the units
Speeds are per hour, so the total time must be in hours too: dividing 40 minutes by 60 gives hour.
Distance = speed × time only works when the time unit matches the speed's unit, so switch minutes into hours first.
Distance is speed times time only when the time unit matches the speed's unit.
▸ Why?
At a steady pace the distance covered is that rate multiplied by the time spent.
▸ Why?
A rate is quoted per one fixed unit, so the count must be measured in that same unit.
Name the unknown and set up
Let r be the rain time in hours; the sun time is then - r. Each distance is speed times time, and the two add to 16 miles.
One variable is enough because the sun time is forced to be the leftover once the rain time is chosen.
7.EE.B.4Introduce A VariableSolve for the rain time
Distribute the 30, combine the r terms, then isolate: 20 - 10r = 16, so 10r = 4 and r = hour.
Peeling operations off one at a time strips the equation down to the value of r.
7.EE.B.4Introduce A VariableConvert back to minutes
The question wants minutes, so multiply by 60 again: × 60 = 24 minutes, choice (C).
Return to the unit the question actually asked for — the answer is 24 minutes, choice (C).
6.RP.A.3Analyze The UnitsName the rain time as one variable, make the sun time the leftover, and add up the distances — the whole race problem shrinks to a single Grade 7 equation.
- Match the units
- Name the unknown and set up
- Solve for the rain time
- Convert back to minutes