AMC 10 · 2010 · #17
Grade 6 logicPick an answer.
AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Name the number of schools with a letter so the total count and Andrea's median rank become simple expressions. The two teammate placements act as boundaries: they squeeze the median rank from above and below (Extreme Principle). Because the total must be odd and the schools count is a whole number, only one choice survives (Eliminate Possibilities).
Name the number of schools
Let n be the number of schools. Each school sends 3 students, so there are 3n students in all.
One letter for the thing you want lets every other quantity be written in terms of it.
6.EE.A.2Introduce A VariableLocate the median rank
A single median needs an odd count, so 3n and n are both odd, and Andrea sits at rank (3n+1)/2.
A single middle value only exists when the list has an odd number of entries.
A single middle value only exists when the list has an odd number of entries.
▸ Why?
The middle of an ordered list is the entry with as many below it as above it.
▸ Why?
An even count leaves two entries sharing the middle, so a lone middle demands an odd count.
Use Beth to bound n above
Andrea beats Beth's 37th, so her rank is at most 36; then (3n+1)/2 ≤ 36 gives n ≤ 23.
Beating a known rank puts a ceiling on where the median can sit.
6.EE.B.8Extreme PrincipleUse Carla to bound n below
Carla's 64th place exists, so 3n ≥ 64; since 3 times 21 is only 63, n ≥ 22.
A place number that actually happened proves at least that many people showed up.
6.EE.B.8Introduce A VariableKeep only the value that fits
So 22 ≤ n ≤ 23 with n odd, and only 23 is odd in that range, so n = 23.
When a whole-number range holds just one value with the right parity, that value is forced.
6.EE.B.5Eliminate PossibilitiesConfirm the count
23 schools give 69 students, an odd count, so Andrea is 35th — ahead of Beth at 37th and Carla at 64th.
Plugging the winner back in should make every clue in the story come out true.
6.SP.A.3Eliminate PossibilitiesName the unknown, turn each clue into a squeeze from above and below, then keep only the whole number with the right parity.
- Name the number of schools
- Locate the median rank
- Use Beth to bound n above
- Use Carla to bound n below
- Keep only the value that fits
- Confirm the count