AMC 10 · 2010 · #5

Grade 4 number-theory
modular-arithmeticpattern-recognitionsystematic-enumeration systematic-enumeration ↑ Prerequisites: modular-arithmetic
📏 Medium solution 💡 2 insights
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Problem
A calendar month has exactly 31 days, and in that month the number of Mondays equals the number of Wednesdays. Of the seven weekdays the 1st of the month could fall on, how many make those two counts equal?

Pick an answer.

(A)
2
(B)
3
(C)
4
(D)
5
(E)
6

AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Make a Systematic List

The clean way to be sure of the count is to write out all seven possibilities for the first day of the month (Tool #2, Make a Systematic List) and test each one. Before listing, Tool #7 (Identify Subproblems) breaks 31 days into "4 whole weeks" plus "3 extra days," which is the key structural fact. Tool #5 (Look for a Pattern) turns that into the rule "the 3 extra days are three consecutive weekdays that slide as the start day slides," so the only thing that ever changes is which three weekdays get a bonus 5th appearance. Tool #3 (Eliminate Possibilities) then gives the crisp test for each row: Mondays equal Wednesdays exactly when both, or neither, of Monday and Wednesday sit in that 3-day block.

1STEP 1

Split 31 into weeks plus leftovers

Seven days make a week, and 31 ÷ 7 = 4 remainder 3 — so the month is 4 whole weeks plus 3 extra days.

31 = 4 × 7 + 3
2STEP 2

Find who gets the bonus day

By weekday the 3 leftovers repeat the first three days: the start weekday and the two after it appear 5 times; everyone else 4.

5-time weekdays = {start, start+1, start+2}
3STEP 3

State the equal-count test

Counts match only if Monday and Wednesday share a fate: both inside the 3-day bonus block (5 each) or both outside it (4 each).

#Mon = #Wed ⇔ Mon, Wed both in block, or both out
4STEP 4

List all 7 starting days

Slide the block over all seven starts: Monday gives {Mon,Tue,Wed} with both in; Thursday and Friday leave both out; the other four split.

equal: Monday, Thursday, Friday unequal: Sun, Tue, Wed, Sat
5STEP 5

Count the winners

Three starting weekdays pass — Monday, Thursday, and Friday — so the count is 3, answer (B).

count = 3 → (B)
Answer
3
Double-check the three winners by actually counting dates. If the 1st is Monday, Mondays fall on 1, 8, 15, 22, 29 (5 of them) and Wednesdays on 3, 10, 17, 24, 31 (5 of them) — equal. If the 1st is Thursday, Mondays are 5, 12, 19, 26 (4) and Wednesdays 7, 14, 21, 28 (4) — equal. If the 1st is Friday, Mondays are 4, 11, 18, 25 (4) and Wednesdays 6, 13, 20, 27 (4) — equal. A failing case confirms the test too: a Sunday start gives Mondays 2, 9, 16, 23, 30 (5) but Wednesdays 4, 11, 18, 25 (4) — unequal. Exactly 3 starting days work, matching (B).
💡Key takeaway

Split 31 days into 4 full weeks plus 3 leftover days: only three weekdays in a row get a bonus 5th appearance, so just check whether Monday and Wednesday are both bonus days or both not — that works out for 3 of the 7 starting days.

  • Split 31 into weeks plus leftovers
  • Find who gets the bonus day
  • State the equal-count test
  • List all 7 starting days
  • Count the winners