AMC 10 · 2010 · #6
Grade 8 geometry-2dPick an answer.
AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The angle we want, ∠ CAB, is one of the two base angles of triangle OAC. The clean move is Tool #4 (Introduce a Variable): call that base angle x. Because OA and OC are both radii, triangle OAC is isosceles, so the OTHER base angle is also x for free — one variable captures two angles. Tool #1 (Draw a Diagram) makes the picture do the heavy lifting: drawing radius OC reveals the isosceles triangle, and seeing A, O, B on one line reveals the straight-angle relationship. Tool #7 (Identify Subproblems) splits the job into two easy pieces — first pin down ∠ AOC from the straight line, then use the triangle's angle sum to solve for x.
Name the base angle x
Draw radius OC. Triangle OAC has OA = OC, so it is isosceles: let x = ∠ CAB, and then ∠ OCA = x too.
Two equal radii force the two base angles to match, so a single letter x stands for both of them.
8.G.A.5Introduce A VariableUse the straight line at O
AB is a diameter, so ∠ AOC and ∠ COB fill the straight angle at O: ∠ AOC = 180° - 50° = 130°.
A straight line is a 180° angle, so the two pieces on either side of OC must add back up to 180°.
A straight line is a straight angle, so the two pieces on either side must add back up to it.
▸ Why?
Angles filling one side of a straight line always add to a straight angle.
▸ Why?
Two equal radii make the two base angles equal, so one letter stands for both.
Solve the angle-sum equation
The angles of triangle OAC sum to 180°, so x + x + 130° = 180°, giving 2x = 50° and ∠ CAB = 25°.
Once the top angle is known, the leftover 50° splits evenly between the two equal base angles.
8.G.A.5Introduce A VariableTwo radii make an isosceles triangle, so its two bottom angles are equal; find the top angle from the straight line, and the leftover splits in half to give 25°.
- Name the base angle x
- Use the straight line at O
- Solve the angle-sum equation