AMC 10 · 2012 · #15
Grade 8 geometry-2d
Pick an answer.
AMC 10 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #1 (Draw a Diagram): the picture is a grid, so I lay a coordinate system on it and read every corner off as a point. Tool #4 (Introduce a Variable): with coordinates in hand, each segment becomes a line equation y=mx+b, and the crossing point C is found by treating its coordinates as unknowns. Tool #7 (Identify Subproblems): I split the work into two clean pieces — first locate C, then use AB as a base to get the area.
Put the figure on a grid
Drop the figure onto a grid: A at the origin, right as +x, down as -y. Then A=(0,0), B=(1,0), and the segment ends are (2,-1) and (0,-2).
A grid of unit squares is already a coordinate plane, so every corner has a whole-number address.
6.NS.C.6Draw A DiagramWrite each segment as a line
From A to (2,-1) the slope is -1/2 through the origin, so y=-1/2x; from B to (0,-2) the slope is 2 through B, so y=2x-2.
Two points fix a line's slope, and the slope plus one point gives its full equation.
8.EE.B.6Introduce A VariableFind where they cross
Set -1/2x=2x-2; doubling both sides gives -x=4x-4, so x=4/5 and y=-2/5, that is C=(4/5,-2/5).
The one point on both lines is exactly the pair (x,y) that satisfies both equations.
The one point on both lines is exactly the pair that satisfies both equations at once.
▸ Why?
A point on a line satisfies that line's equation, and this point lies on both.
▸ Why?
Setting the two rules equal and simplifying keeps the statement true, so the point can be solved for.
Turn the corner into area
Base AB sits flat on y=0 with length 1, and the height is |-2/5|=2/5, so the area is 1/2·1·2/5=1/5 — choice (B).
When the base sits on a horizontal line, the height is just how far the third point is above or below it.
6.G.A.1Identify SubproblemsDrop the picture onto a grid, turn each slanted segment into a line equation, solve the two lines together to find where they cross, then use the flat side AB as a base — the area comes out to 1/5, choice (B).
- Put the figure on a grid
- Write each segment as a line
- Find where they cross
- Turn the corner into area