Competition · AMC preparation · step 4 of 4
AMC 10 · 2012A · #3
Grade 6 arithmeticPick an answer.
AMC 10 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The bug moves along positions on a number line, so the natural first move is Tool #1: sketch the line and mark -2, -6, and 5. The picture instantly shows the trip has two straight legs in opposite directions. Tool #7 then splits the whole crawl into those two subproblems — leg one from -2 to -6, leg two from -6 to 5 — each an easy distance on its own. Tool #8 keeps the focus on "units of distance," reminding us that a distance is always the positive gap between two points (never a negative), so the two legs simply add up.
Draw the number line
Sketch a number line and mark the start -2, the turning point -6, and the end 5.
Seeing the points on the line makes the two separate crawls obvious at a glance.
6.NS.C.6Draw A DiagramLength of leg one
Leg one runs from -2 to -6, so its length is the absolute value of the difference: 4 units.
From -2 to -6 you step across 4 tick marks, so that leg is 4 units long.
6.NS.C.7Identify SubproblemsLength of leg two
Leg two runs from -6 to 5, and the same absolute value of the difference gives 11 units.
Crossing 0 from -6 up to 5 covers 6 units to reach 0 and 5 more after it, which is 11 units.
6.NS.C.7Identify SubproblemsAdd the two legs
The total crawl is the sum of the two legs: 4 + 11 = 15 units.
Total distance is just the first leg plus the second leg, so the bug crawls 15 units in all.
The total distance is just the first leg plus the second leg.
▸ Why?
The crawl is exactly its two legs put end to end, so their lengths add.
▸ Why?
Each leg's length is the gap between its two ends, read off in order along the line.
Distance is always the positive gap between two points, so when something turns around you add each leg separately: 4 + 11 = 15 units.
- Draw the number line
- Length of leg one
- Length of leg two
- Add the two legs
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