AMC 10 · 2012 · #6

Grade 8 arithmetic
systems-of-equationsfraction-arithmetic convert-to-algebra ↑ Prerequisites: linear-equations-one-var
📏 Medium solution 💡 2 insights
Problem
Two positive numbers multiply to 9. The reciprocal of one number is 4 times the reciprocal of the other. Find the sum of the two numbers.

Pick an answer.

(A)
$\frac{10}{3}$
(B)
$\frac{20}{3}$
(C)
7
(D)
$\frac{15}{2}$
(E)
8

AMC 10 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Introduce a Variable

Two unknown numbers are tied together by two facts: a product and a reciprocal relationship. Naming each number with a letter lets me turn both facts into equations, then combine them into one equation in a single variable and solve it.

1STEP 1

Name the two numbers

Call the two positive numbers a and b, so each fact can be written as an equation instead of words.

a, b > 0
2STEP 2

Turn the two facts into equations

"The product is 9" becomes ab = 9; "one reciprocal is 4 times the other" becomes 1/a = 4·(1/b).

ab = 9, 1/a = 4/b
3STEP 3

Simplify the reciprocal equation

Cross-multiplying 1/a = 4/b gives b = 4a: one number is 4 times the other.

1/a = 4/b → b = 4a
4STEP 4

Substitute and solve for a

Replacing b in ab = 9 gives 4a² = 9, so a² = 9/4, and a is positive, so a = 3/2.

a · 4a = 9 → 4a² = 9 → a² = 9/4 → a = 3/2
5STEP 5

Find b and add

Then b = 4a = 6, and the sum is 3/2 + 12/2 = 15/2, choice (D).

b = 6, a + b = 3/2 + 6 = 15/2
Answer
15/2
Check both facts with a=3/2 and b=6: the product is 3/2 · 6 = 9 (correct), and 1/a = 2/3 while 1/b = 1/6, and indeed 2/3 = 4·1/6 (correct). The sum 15/2 = 7.5 matches choice (D).
💡Key takeaway

Turn each sentence into an equation, use one fact to replace a letter, and you shrink two unknowns down to one you can solve.

  • Name the two numbers
  • Turn the two facts into equations
  • Simplify the reciprocal equation
  • Substitute and solve for a
  • Find b and add