AMC 10 · 2013 · #1
Grade 5 arithmeticPick an answer.
AMC 10 2013 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The expression is built from small pieces, so Tool #7 (Identify Subproblems) breaks it into three easy jobs: add each group of numbers, reduce the two fractions, then subtract. Tool #3 (Eliminate Possibilities) uses the shape of the problem as a guardrail — the first fraction is bigger than 1 and the second is smaller than 1, so their difference is a small positive number, which throws out the negative choice (A) and the large choices (D) and (E) before any careful arithmetic.
Add the numbers in each group
The top group is 2+4+6=12, the bottom 1+3+5=9, so the expression becomes 12/9-9/12 — the same two numbers, swapped.
Doing the repeated addition once turns a scary-looking expression into two plain fractions.
2.NBT.B.5Identify SubproblemsReduce each fraction
Divide top and bottom of each by 3: 12/9 becomes 4/3 and 9/12 becomes 3/4, so the problem is 4/3-3/4 — two flips of each other.
Dividing the top and bottom by the same number keeps a fraction's value but makes the digits smaller.
Dividing the top and bottom by the same number keeps a fraction's value but shrinks its digits.
▸ Why?
Scaling top and bottom together leaves a different-looking fraction naming the same amount.
▸ Why?
That shared factor over itself is one, and multiplying by one changes nothing.
Subtract using a common denominator
Over the common denominator 12, 4/3=16/12 and 3/4=9/12, so 16/12-9/12=7/12 — choice (C).
Fractions can only be subtracted once they are cut into the same-size pieces, so match denominators first.
5.NF.A.1Eliminate PossibilitiesAdd the repeated groups first, then subtract the two fractions over a common denominator — a bigger-than-one fraction minus a smaller-than-one fraction leaves a small positive number.
- Add the numbers in each group
- Reduce each fraction
- Subtract using a common denominator