AMC 10 · 2013 · #10
Grade 7 algebraPick an answer.
AMC 10 2013 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Two unknown counts are linked by a scoring total and a ratio. Name each count with a letter, translate every sentence into an equation, and track the point units so the totals line up. Then substitution collapses it to one equation in one variable.
Name the two counts
Let x be the number of two-point shots attempted and y the number of three-point shots attempted.
Give each unknown a letter so the word sentences can become equations.
6.EE.B.6Introduce A VariableTranslate 50% more
"50% more than y" is y plus half of y, so x = 1.5y.
"50% more" is the original amount plus half of it again.
Fifty percent more is the original amount plus half of it again.
▸ Why?
A percent is a count out of a hundred of the stated base, and fifty out of a hundred is a half.
▸ Why?
The larger amount is exactly the original plus the added share, so both pieces are counted.
Count the points
Twos give 0.5x made at 2 points each, threes give 0.4y made at 3 each, so x + 1.2y = 54.
Made shots times point value, added up, must hit the score.
7.RP.A.3Analyze The UnitsSubstitute and solve
Swap x for 1.5y: 1.5y + 1.2y = 2.7y = 54, so y = 20 three-point attempts, choice (C).
One substitution turns two unknowns into one solvable equation.
7.EE.B.4Introduce A VariableName each unknown with a letter, turn every sentence into an equation, then swap one variable in for the other so only one is left to solve.
- Name the two counts
- Translate 50% more
- Count the points
- Substitute and solve