AMC 10 · 2015 · #11
Grade 8 geometry-2dPick an answer.
AMC 10 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The size is never given, only the shape, so Tool #4 (Introduce a Variable) lets us write the sides as 4x and 3x — one unknown x carries the unknown size while locking in the 4:3 shape. Tool #1 (Draw a Diagram) shows the diagonal cutting the rectangle into a right triangle, which is the bridge from the sides to d. Then Tool #13 (Convert to Algebra) turns "area = k d²" into an equation in x; the x cancels, leaving the pure number k the problem asks for.
Name the sides with one variable
Let the sides be 4x and 3x, so the 4:3 ratio holds automatically.
A ratio fixes the shape but not the size, so one scale factor x captures every rectangle of that shape at once.
6.RP.A.3Use Matrix LogicUse the diagonal's right triangle
By the Pythagorean theorem, d² = (4x)² + (3x)² = 25x².
A rectangle's diagonal always closes a right triangle with its two sides, so Pythagoras ties d straight to x.
8.G.B.7Draw A DiagramWrite the area and cancel x
Area = 12x² = 12/25 d², so k = 12/25 — choice (C).
Because both area and d² carry the same x², the unknown size divides out and leaves a pure number.
6.EE.A.2Convert To AlgebraCall the sides 4x and 3x; the diagonal gives d²=25x² and the area is 12x², so the area is always 12/25 of d².
- Name the sides with one variable
- Use the diagonal's right triangle
- Write the area and cancel x