AMC 10 · 2015 · #8
Grade 8 rate-ratioPick an answer.
AMC 10 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The puzzle mixes two snapshots in the past with a question about the future, so the safest move is to anchor everything to one fixed moment: now. Tool #4 (Introduce a Variable) names Pete's and Claire's current ages as P and C; every other age in the story is then just P or C shifted by 2 or 4 years. Tool #13 (Convert to Algebra) turns the two word-facts into two equations, which lock down P and C. Once the present ages are known, the future ratio question becomes one more short equation to solve for the number of years.
Name the present ages
Let P and C be Pete's and Claire's ages now; past ages are P and C minus the shift.
Anchoring every age to one moment turns a confusing timeline into simple add-or-subtract shifts.
6.EE.B.6Use Matrix LogicTranslate the two facts
The two facts become two equations: P-2 = 3(C-2) and P-4 = 4(C-4).
Each English sentence about ages becomes one equation once you write the shifted ages in symbols.
6.EE.A.2Convert To AlgebraSolve the system for the ages
Solving both for P and setting them equal gives C = 8, so P = 20.
Two true facts about the same two people leave exactly one pair of ages that fits both.
8.EE.C.8Convert To AlgebraWrite the future-ratio equation
In x years Pete is 20+x, Claire is 8+x; a 2:1 ratio means 20 + x = 2(8 + x).
A ratio of 2:1 is just the statement that one quantity equals twice the other.
7.RP.A.2Convert To AlgebraSolve for the number of years
Solving gives x = 4 years — choice (B).
Solving the single equation pins down the one future moment when the ratio works.
8.EE.C.7Convert To AlgebraPin every age to today as P and C, let the two clues fix the present ages, then ask how many years make Pete exactly twice Claire.
- Name the present ages
- Translate the two facts
- Solve the system for the ages
- Write the future-ratio equation
- Solve for the number of years