AMC 10 · 2016 · #4
Grade 7 number-theoryPick an answer.
AMC 10 2016 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The formula looks heavy, but it is really three small jobs done in order, which is exactly what Tool #7 (Identify Subproblems) is for: first divide x by y, then take the floor of that quotient, then substitute back and subtract. Tool #4 (Introduce a Variable) keeps x=3/8 and y=-2/5 straight so each piece drops into the right slot. Tool #3 (Eliminate Possibilities) gives a fast sanity check: the result must be negative with denominator 40, which already points at one choice.
Plug the numbers into the formula
Put x=3/8 and y=-2/5 into the formula to get 3/8-(-2/5)⌊ (3/8)/(-2/5)⌋; the only tricky piece is the floor.
A formula is just a fill-in-the-blank: put each given number where its letter sits.
6.EE.A.2Use Matrix LogicDivide the two fractions
Dividing by a fraction flips it: 3/8÷(-2/5)=3/8·(-5/2), and one minus sign makes the quotient -15/16.
Flip-and-multiply turns a messy fraction-over-fraction into one clean fraction, and one minus sign makes it negative.
7.NS.A.2Identify SubproblemsTake the floor of a negative number
-15/16=-0.9375 sits between -1 and 0, and floor steps left to the greatest integer below it, so ⌊ -15/16⌋=-1, not 0.
Floor always steps left to the nearest integer, so a number just below zero lands on -1.
6.NS.C.7Identify SubproblemsSubstitute back and subtract
With the floor known, 3/8-(-2/5)(-1)=3/8-2/5=15/40-16/40=-1/40, which is (B).
With the floor pinned down, the whole formula collapses to one ordinary fraction subtraction.
7.NS.A.1Identify SubproblemsFloor always rounds down toward smaller numbers, so a value just below zero like -0.9375 drops to -1, not 0.
- Plug the numbers into the formula
- Divide the two fractions
- Take the floor of a negative number
- Substitute back and subtract