AMC 10 · 2016 · #1
Grade 8 algebraPick an answer.
AMC 10 2016 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is one compound calculation stacked on top of another, so Tool #7 (Identify Subproblems) is the natural fit: first figure out what a⁻¹ is, then build the numerator, then divide by a. Each piece is a small, safe step. Tool #4 (Introduce a Variable) keeps the meaning of a⁻¹ front and center — a negative exponent is just 1/a — so the symbol does not become a trap.
Translate the negative exponent
A negative exponent flips the base into its reciprocal, so a⁻¹ = , and the reciprocal of is 2.
A negative-one exponent just flips the number over, and flipping 1/2 gives 2.
A negative-one exponent just flips the number over.
▸ Why?
That flip is what undoes multiplying by the number, returning it to one.
▸ Why?
A number times its flip is one, and multiplying by one changes nothing.
Build the numerator
Substitute a⁻¹ = 2 into the top 2a⁻¹ + : that is 2·2 + = 4 + 1 = 5.
Once a⁻¹ is a plain number, the numerator is ordinary arithmetic you can do left to right.
6.EE.A.2Identify SubproblemsDivide the numerator by a
Divide the top by a: 5 ÷ () = 5·2 = 10, which is choice (D).
Dividing by 1/2 asks "how many halves fit in 5?" — and that is 10.
6.NS.A.1Identify SubproblemsTurn the negative exponent into a reciprocal first, then it is just plug-in-and-compute that you already know.
- Translate the negative exponent
- Build the numerator
- Divide the numerator by a