AMC 10 · 2017 · #17
Grade 8 geometry-2dPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
A ratio is largest when its top is as big as possible and its bottom as small as possible, so this is a boundary problem: maximize PQ and minimize RS separately. First list every lattice point on the circle (a finite, small set), then push each chord to its extreme while keeping both lengths irrational.
List the lattice points
Solve x² + y² = 25 over the integers; allowing both signs on the pairs (0,5), (3,4), (4,3) gives twelve points.
There are only a handful of lattice points on a circle this small, so you can write them all down.
6.NS.C.8Make A Systematic ListWhen is a chord irrational?
A chord's length is the square root of a sum of squared coordinate gaps, irrational exactly when that sum is not a perfect square.
The square root of a whole number is irrational unless that whole number is a perfect square.
8.G.B.8Draw A DiagramMake RS as small as possible
Neighbors like (3, 4) and (4, 3) give the tightest gap, so the smallest irrational chord is RS = √2.
Adjacent lattice points on the circle are only one step apart in each coordinate, the tightest spacing available.
8.G.B.8Evaluate Finite DifferencesMake PQ as large as possible
The diameter (10) is rational, so the longest irrational chord joins near-opposite points like (-3, 4) and (4, -3): PQ = 7√2.
Skip the diameter because it is rational, and the best you can do is a chord just shy of it.
8.G.B.8Evaluate Finite DifferencesForm the ratio
The matching √2 factors cancel, so PQ/RS = 7; the four points are distinct, making this ratio attainable — answer (D).
Both lengths carry the same sqrt(2), so the irrational part divides out and a whole number is left.
8.NS.A.2Evaluate Finite DifferencesTo make a ratio as big as possible, make the top as large as you can and the bottom as small as you can, then watch the matching square roots cancel.
- List the lattice points
- When is a chord irrational?
- Make RS as small as possible
- Make PQ as large as possible
- Form the ratio