AMC 10 · 2017 · #2
Grade 4 arithmeticPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #14 (Extreme Principle): the question asks for the greatest number of popsicles, so push toward the most popsicles per dollar and use every dollar. Tool #8 (Analyze the Units): what really matters is popsicles per dollar, so compare the three deals on equal footing before buying anything. Tool #6 (Guess and Check): after building the best buy, test a few other ways to split the $8 to make sure none of them gives more.
Compare the three deals
Line the deals up over $6: singles give 6, three $2 boxes give 3×3=9, two $3 boxes give 2×5=10 — the 5-popsicle box wins.
Judging deals at the same price tag shows which one stretches a dollar the furthest.
4.NBT.B.5Analyze The UnitsBuy the best box as much as possible
Each $3 box gives 5, so two cost $6 for 10 popsicles, leaving $8-$6=$2 — a third box needs $3, so two is the max.
Loading up on the best deal first squeezes the most popsicles out of most of the money.
4.NBT.B.4Evaluate Finite DifferencesSpend the last two dollars
With $2 left, a 3-popsicle box beats two singles, so add it: 10+3=13 popsicles, every dollar spent.
Even the leftover money should go to the better popsicles-per-dollar choice.
4.NBT.B.4Analyze The UnitsCheck no split beats 13
Rivals fall short: four $2 boxes give 4×3=12, and a $3 box plus two $2 boxes plus a single also give 12 — 13 stays best, choice (D).
Trying the natural rivals confirms the best buy really is the biggest.
4.OA.A.3Guess And CheckFind the best popsicles-per-dollar deal, buy as many as you can, then spend the leftover on the next-best deal: two $3 boxes plus one $2 box make 13 popsicles — choice (D).
- Compare the three deals
- Buy the best box as much as possible
- Spend the last two dollars
- Check no split beats 13