AMC 10 · 2017 · #9
Grade 7 rate-ratioPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The units carry the whole problem: time equals distance divided by speed, so km ÷ km/h gives hours. Tool #8 (Analyze the Units) fixes that relationship and reminds us to finish in minutes. Tool #7 (Identify Subproblems) splits each loop into its three legs, each a one-line division. Tool #1 (Draw a Diagram) tracks which leg is uphill, downhill, or flat for each rider once the directions are reversed.
Time is distance over speed
On any leg a rider holds one speed, so its time is distance divided by speed — km ÷ km/h leaves hours. Convert to minutes at the end.
Dividing a distance by a speed cancels the kilometers and leaves the time.
6.RP.A.2Analyze The UnitsMinnie's three legs
Minnie: 10 km uphill at 5 kph, 15 km downhill at 30 kph, 20 km flat at 20 kph, giving 2 + ½ + 1 = 3.5 hours = 210 minutes.
Each leg is one division, and the slow uphill climb eats most of the time.
6.RP.A.3Identify SubproblemsFlip the slopes for Penny
Penny rides backwards A→C→B→A: the flat stays flat, but Minnie's downhill B→C now climbs for Penny and her uphill A→B now falls.
Going the other way turns every climb into a descent and every descent into a climb.
6.RP.A.3Draw A DiagramPenny's three legs
Penny: 20 km flat at 30 kph, 15 km uphill at 10 kph, 10 km downhill at 40 kph, giving 2/3 + 3/2 + 1/4 = 29/12 hours = 145 minutes.
Putting the three fractional hours over a shared bottom lets them add into one number.
5.NF.A.1Identify SubproblemsSubtract the two times
Minnie needs 210 minutes, Penny 145, so Minnie takes 210 − 145 = 65 minutes more. The answer is (C).
The extra time is just the gap between the two totals.
7.NS.A.3Analyze The UnitsSplit a trip into legs, find each leg's time as distance divided by speed, and remember that riding the loop backwards turns every hill into the opposite slope.
- Time is distance over speed
- Minnie's three legs
- Flip the slopes for Penny
- Penny's three legs
- Subtract the two times