AMC 10 · 2017 · #5
Grade 7 arithmeticPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Two amounts move together under one rule, so Tool #4 (Introduce a Variable) leads: call the cherry count c, and the blueberry count becomes 2c for free. Tool #13 (Convert to Algebra) turns the after-eating sentence into a single equation 2c-10=3(c-10). Solving that one equation gives c, and then 2c answers the question. Tool #3 (Eliminate Possibilities) offers a fast multiple-choice backup: the original blueberry count minus 10 must be a positive multiple of 3, which only one choice satisfies. Tool #6 (Guess and Check) lets us plug the result back to confirm the wording holds.
Name the two counts with one variable
Let c be the cherry count. Since blueberry is twice cherry, the blueberry count is 2c.
Naming cherry as c makes blueberry ride along as 2c, so there is really only one unknown.
6.EE.A.2Use Matrix LogicTranslate the after-eating sentence
Eating 10 of each drops the counts to 2c-10 and c-10; blueberry being three times cherry gives 2c-10=3(c-10).
“Three times as many” is just the word × 3 written as an equation.
7.EE.B.4Convert To AlgebraSolve for the cherry count
Expand and collect the c terms: 2c-10=3c-30, so c=20 cherry jelly beans.
Lining up the c terms on one side leaves a single number on the other.
7.EE.B.4Use Matrix LogicFind the original blueberry count
Double the cherry count: blueberry = 2c = 2×20 = 40, choice (D).
Double the cherry count gives the blueberry count the problem wants.
6.EE.A.2Use Matrix LogicCall cherry c and blueberry 2c, write what happens after eating 10 of each as one equation, solve it, and double the answer — 40, choice (D).
- Name the two counts with one variable
- Translate the after-eating sentence
- Solve for the cherry count
- Find the original blueberry count