AMC 10 · 2017 · #7
Grade 7 rate-ratioPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #4 (Introduce a Variable): the bike half and the walk half cover the same unknown distance, so name that one distance d and both parts are described at once. Tool #8 (Analyze the Units): the speeds are kilometers per hour, so each time must be d ÷ speed in hours, which means the 44 minutes has to become a fraction of an hour first. Tool #7 (Identify Subproblems): split the 44 minutes into the bike time plus the walk time, write each as d over its speed, add them, and solve the single equation for d.
Name the equal half-distance
Let d be each equal half — the biked part and the walked part — so she bikes d and walks d, and d is the answer.
One letter covers both halves because they are the same length.
7.EE.B.4Use Matrix LogicWrite each part's time
Time = distance ÷ speed, so biking d at 17 km/h takes d/17 hour and walking d at 5 km/h takes d/5 hour.
Dividing distance by speed always gives the time the trip lasts.
6.RP.A.3Analyze The UnitsTurn 44 minutes into hours
Speeds are per hour, so the time must be too: 44 minutes = 44/60 = 11/15 hour.
Match the time unit to the speed unit before adding anything.
6.RP.A.3Analyze The UnitsAdd the times and solve
Bike time + walk time = trip: d/17 + d/5 = 11/15, i.e. 22d/85 = 11/15, so d = 935/330.
The two part-times stacked together must fill the whole 44 minutes.
5.NF.A.1Identify SubproblemsRound to the nearest tenth
Divide: 935/330 = 2.8333… km. The next digit is 3, so it rounds down to 2.8 — choice (C).
Look at the next digit to decide whether the tenths digit stays or rises.
5.NBT.A.4Identify SubproblemsCall the equal half-distance d; biking takes d/17 hour and walking takes d/5 hour, and together they fill 44/60 hour, which gives d ≈ 2.8 kilometers — choice (C).
- Name the equal half-distance
- Write each part's time
- Turn 44 minutes into hours
- Add the times and solve
- Round to the nearest tenth