AMC 10 · 2018 · #3
Grade 3 algebraPick an answer.
AMC 10 2018 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
A "how many different values" question with a small finite setup points straight at Tool #2 (Make a Systematic List). But listing all 4! = 24 ways to fill the blanks would be wasteful, so first apply Tool #15 (Organize Information in More Ways): because both × and + are commutative, the only thing that matters is how the four digits split into two pairs. That reframing turns 24 messy arrangements into just a handful of pairings to list. Tool #3 (Eliminate Possibilities) then confirms the count against the answer choices.
Order inside and between products does not matter
Since a× b = b× a and P+Q = Q+P, the total depends only on how the four digits split into two pairs, not on any order.
Commutativity means rearranging factors or swapping the two products never changes the result, so all 24 fillings collapse onto just the distinct pairings.
3.OA.B.5Organize Information In More WaysList the ways to split into two pairs
Fix digit 1 and choose its partner from 2, 3, or 4; the rest pair up automatically, giving three splits with none repeated or missed.
Fixing one digit and choosing its partner is the systematic rule that lists every pairing once and only once.
3.OA.A.3Make A Systematic ListMultiply each pair
For each split, multiply the two digits in each pair to get the two products that will be added.
Each pairing just needs two small single-digit multiplications before adding.
3.OA.C.7Make A Systematic ListAdd the two products in each split
Add each split's two products to get its total: 14, 11, and 10.
Summing the two products turns each pairing into a single final number to compare.
2.OA.B.2Make A Systematic ListCount the distinct totals
The totals 14, 11, 10 are all different, so there are three distinct values — choice (B), not the order-counting traps 6 or 24.
Once each pairing gives one number, counting the different results is just sorting them into distinct buckets and counting the buckets.
K.MD.B.3Eliminate PossibilitiesBecause × and + don't care about order, the only choice is how to split 1,2,3,4 into two pairs — and there are just three ways, giving 14, 11, 10.
- Order inside and between products does not matter
- List the ways to split into two pairs
- Multiply each pair
- Add the two products in each split
- Count the distinct totals