AMC 10 · 2021 · #9
Grade 8 arithmeticPick an answer.
AMC 10 2021 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #11 (Work Backwards): the problem hands us the end state and asks for the start — undo the reflection first, then undo the rotation. Tool #7 (Subproblems): each transformation is its own self-contained inverse. Tool #1 (Diagram): sketch the four key points (final image, post-rotation image, rotation center C, and P) on a quick coordinate grid to keep signs straight. Tool #3 (Eliminate): the answer is one of {1, 3, 5, 7, 9} — all odd — so a parity sanity-check (if a, b are integers, b - a inherits the right parity) is built in.
Reflection over y = -x is its own inverse, so apply it again to (-6, 3), giving (-3, 6) — the point right after the rotation.
Grade 8 reflections: reflecting twice over the same line returns the original.
8.G.A.1Work BackwardsUndo the rotation by first translating so C sits at the origin: (-3, 6) - (1, 5) = (-4, 1).
Grade 8 translation: shift the center to the origin so a simple rotation rule applies.
8.G.A.3Identify SubproblemsRotate 90° clockwise about the origin with the rule (x, y) → (y, -x): (-4, 1) becomes (1, 4).
Grade 8 rotation: 90° CW sends (x, y) → (y, -x).
8.G.A.1Work BackwardsTranslate back by adding C: (1, 4) + (1, 5) = (2, 9), so P = (a, b) with a = 2, b = 9.
Grade 8 translation: undo the shift to land back in the original coordinate system.
8.G.A.3Identify SubproblemsSubtract: b - a = 9 - 2 = 7, which is choice (D).
Grade 4 subtraction: 9 - 2 = 7, exactly choice (D).
4.NBT.B.4Eliminate PossibilitiesThis AMC 10 problem only needs Grade 8 transformation rules you already know — reflect over y = -x (a self-inverse) to undo step 2, then translate to center, 90° CW rotate, translate back to undo step 1. Starting from (-6, 3), the chain gives P = (2, 9), so b - a = 9 - 2 = 7, choice (D).