AMC 10 · 2004 · #12

Grade 8 geometry-2d
coordinate-geometryslope-interceptsystems-of-equations convert-to-algebraidentify-subproblems ↑ Prerequisites: linear-equations-two-var
📏 Medium solution 💡 2 insights
Problem
Two points sit on the y-axis: A=(0,9) and B=(0,12). Two more points, A' and B', sit somewhere on the line y=x. The segment from A to A' and the segment from B to B' cross each other at C=(2,8). Find the length of the segment A'B'.

Pick an answer.

(A)
2
(B)
$2\sqrt2$
(C)
3
(D)
$2 + \sqrt 2$
(E)
$3\sqrt 2$
How to solve
Strategy Introduce a Variable

The two unknown points are pinned down by two facts each: they sit on y=x, and they are collinear with a known pair of points. Tool #4 turns both facts into equations — write A'=(a,a) and B'=(b,b) so that the line condition is already built in, leaving one unknown per point. Each line is easy to write down because A and B are on the y-axis, so the y-intercept is handed to us and only the slope has to be computed from C. Tool #1 keeps the configuration honest: after solving, the sketch has to be checked to confirm C really falls inside both segments and that A'B' lies along the 45° line.

1STEP 1

Give the unknown points coordinates

A point on that line has matching coordinates, so each unknown costs one number.

A'=(a,a), B'=(b,b)
2STEP 2

Find the line through A and C

The first two known points give a line with intercept read straight off the axis: slope -1/2.

slope = (8-9)/(2-0) = -1/2 ⟹ y = -1/2x + 9
3STEP 3

Intersect that line with y = x

Intersecting with the diagonal gives A' = (6,6).

a = -1/2a + 9 ⟹ 3/2a = 9 ⟹ a = 6, A'=(6,6)
4STEP 4

Repeat for B and C

The same two moves on the other segment give B' = (4,4).

slope=(8-12)/(2-0)=-2 → y=-2x+12; b=-2b+12 → b=4, B'=(4,4)
5STEP 5

Check C is inside both segments

Checking confirms the crossing really lies inside both segments.

0 < 2 < 6 and 0 < 2 < 4; midpoint of BB' = ((0+4)/2,(12+4)/2) = (2,8) = C
6STEP 6

Measure A'B'

Equal horizontal and vertical changes give length 2√(2), choice (B).

|A'B'| = √((6-4)² + (6-4)²) = √(8) = 2√(2) → (B)
Answer
2√2
Both answers satisfy every condition: A'=(6,6) and B'=(4,4) have equal coordinates, so they are on y=x. Putting x=2 into y=-1/2x+9 gives 8, and into y=-2x+12 also gives 8, so both segments really pass through C=(2,8). The size is sensible too: 2√2≈ 2.83, between choices (A) 2 and (C) 3, which is exactly what a 45° segment with a horizontal gap of 2 should measure. Choices 2 and 3 would require the segment not to be at 45°, and 3√2 would need a horizontal gap of 3.
💡Key takeaway

Write a point on the line y = x as (t, t), and each straight-line condition becomes one easy equation — here they give (6,6) and (4,4), a distance of 2 times the square root of 2.

  • Give the unknown points coordinates
  • Find the line through A and C
  • Intersect that line with y = x
  • Repeat for B and C
  • Check C is inside both segments
  • Measure A'B'