AMC 10 · 2004 · #15

Grade 7 rate-ratio
rateratio-proportion physical-representationconvert-to-algebra ↑ Prerequisites: ratio-proportion
📏 Medium solution 💡 2 insights
Problem
Two runners start at opposite ends of a circular track and run in opposite directions at constant speeds. How far each has run by their first and second meetings is given. Find the length of the track.

Pick an answer.

(A)
250
(B)
300
(C)
350
(D)
400
(E)
500
How to solve
Strategy Draw a Diagram

Sketching the circle turns the word problem into distances you can add. Once you see how far the two runners cover together before each meeting, constant speed lets you compare the two stretches by simple proportion instead of heavy algebra.

1STEP 1

Distance covered together at first meeting

Starting opposite each other, their two distances fill exactly half a lap at the first meeting.

Brenda + Sally = L/2
2STEP 2

Distance covered together between meetings

Meeting again means they together cover one full lap between the meetings.

Brenda + Sally = L (between the two meetings)
3STEP 3

The second stretch is twice the first

Constant speeds make the second stretch exactly twice the first for each runner.

1/2L → L → each distance × 2
4STEP 4

Add the second-stretch distances

Adding the two second-stretch distances gives the lap: 350, choice (C).

L = 2 × 100 + 150 = 350
Answer
350
Check that the speed ratio stays constant. In the first stretch Brenda runs 100 m and Sally runs 175 - 100 = 75 m, a ratio of 4:3. In the second stretch Brenda runs 200 m and Sally runs 150 m, also 4:3. The ratio matches in both stretches, and 350 is one of the answer choices, so the result holds together.
💡Key takeaway

On a circular track, two runners together cover half a lap before their first meeting and a full lap between each meeting after.

  • Distance covered together at first meeting
  • Distance covered together between meetings
  • The second stretch is twice the first
  • Add the second-stretch distances