AMC 10 · 2004 · #15

Grade 6 arithmetic
digit-decompositionlinear-diophantineplace-value convert-to-algebraguess-and-check ↑ Prerequisites: place-value
📏 Medium solution 💡 3 insights
Problem
Two ages are two-digit numbers built from the same two digits, written in reverse order. Five years from now, the older will be exactly twice the younger. Find the difference between their ages right now.

Pick an answer.

(A)
9
(B)
18
(C)
27
(D)
36
(E)
45
How to solve
Strategy Introduce a Variable

The two ages are locked together by their digits, so Tool #4 (Introduce a Variable) is the natural start: call the tens digit of one age a and the ones digit b, and the reversal writes itself as 10a+b and 10b+a. The 'twice as old in five years' sentence then becomes a single equation. That equation, 8a=19b+5, has two digit-unknowns but only one equation — so instead of grinding algebra, Tool #6 (Guess and Check) walks b through 0,1,2,… and Tool #3 (Eliminate Possibilities) throws out every value that fails to leave a a single digit. Only one pair survives.

1STEP 1

Name the two digits

Naming the two digits writes both ages with one pair of unknowns.

Jack=10a+b, Bill=10b+a
2STEP 2

Turn the words into an equation

The five-years-later sentence becomes a single equation.

10a+b+5 = 2 (10b+a+5)
3STEP 3

Simplify to one clean relation

Simplifying ties the two digits into one clean relation.

10a+b+5=20b+2a+10 → 8a=19b+5
4STEP 4

Test digit values for b

Only single digits are allowed, and just one pair fits: 31 and 13.

b=1: 8a=24→ a=3 → Jack=31, Bill=13
5STEP 5

Take the difference

The difference is 18, matching nine times the digit gap, choice (B).

31-13 = 9(a-b) = 9(3-1) = 18 (B)
Answer
18
Check the ages against the story. In five years Jack is 31+5=36 and Bill is 13+5=18, and 36=2 × 18, exactly 'twice as old.' The two ages, 31 and 13, really are the same digits reversed, and their difference 18 sits right on choice (B). It even makes sense that every answer choice is a multiple of 9, since any reversed-digit pair differs by 9(a-b) — the test is which multiple actually satisfies the age condition.
💡Key takeaway

Write the two ages as 10a+b and 10b+a, turn 'twice as old in five years' into one equation, and testing single digits leaves only 31 and 13 — a difference of 18.

  • Name the two digits
  • Turn the words into an equation
  • Simplify to one clean relation
  • Test digit values for b
  • Take the difference