AMC 10 · 2005 · #1

Grade 6 arithmetic
percentagelinear-equations-one-var convert-to-algebrawork-backwards ↑ Prerequisites: percentagefraction-arithmetic
📏 Short solution 💡 1 insight
Problem
The number 2 is 10 percent of one number and 20 percent of another. Find the difference between those two numbers.

Pick an answer.

(A)
1
(B)
2
(C)
5
(D)
10
(E)
20
How to solve
Strategy Convert to Algebra

Each English sentence hides one multiplication, so turning the words into two equations makes the problem mechanical. Each equation gives a part and asks for the whole, which is a backwards question: undo the multiplication. The request x - y splits cleanly into three small jobs — find x, find y, subtract — so solve them in that order.

1STEP 1

Turn the first sentence into an equation

The first sentence says a whole was shrunk to a tenth.

10/100 x = 1/10x = 2
2STEP 2

Undo the tenth to recover x

Undoing that shrinking recovers 20.

1/10x = 2 ⟹ x = 2 × 10 = 20
3STEP 3

Repeat the move for y

The same move on a fifth recovers 10.

20/100 y = 1/5y = 2 ⟹ y = 2 × 5 = 10
4STEP 4

Subtract to finish

Subtracting gives 10, choice (D).

x - y = 20 - 10 = 10
Answer
10
Check both original sentences against the recovered numbers: 10% of 20 is 2, and 20% of 10 is 2. Both hold, so x = 20 and y = 10 are right, and x - y = 10. A second, structural check agrees: 20% is exactly twice 10%, so to yield the same part 2 the second whole must be half the first, giving y = x/2 and therefore x - y = x/2 = 10.
💡Key takeaway

A percent tells you how the part was made from the whole, so running that one step backwards hands you the whole.

  • Turn the first sentence into an equation
  • Undo the tenth to recover x
  • Repeat the move for y
  • Subtract to finish