AMC 10 · 2006 · #19

Grade 10 geometry-2d
coordinate-geometrytangent-circlesslope-intercept convert-to-algebracasework ↑ Prerequisites: coordinate-geometryslope-intercept
📏 Long solution 💡 4 insights 📊 Diagram
Problem
A line touches two circles and keeps both on the same side of it. It has positive slope. Find where it crosses the vertical axis.

Pick an answer.

(A)
$\frac{908}{119}$
(B)
$\frac{909}{119}$
(C)
$\frac{130}{17}$
(D)
$\frac{911}{119}$
(E)
$\frac{912}{119}$
How to solve
Strategy Convert to Algebra

Tool #13 (Convert to Algebra) is the spine: the words "tangent" and "external" each translate into one exact equation about the distance from a center to the line, so the whole geometry problem becomes two equations in the two unknowns m and b. Tool #1 (Diagram) fixes which side of the line each circle is on, which is the only place the word "external" lives. Tool #4 (Introduce a Variable) handles that side information cleanly with a single sign symbol ε = ± 1 instead of splitting into a mess of absolute-value cases. Tool #7 (Subproblems) splits the work in the right order: subtracting the two equations kills b and leaves a one-variable equation for m, so find m first, then b. Tool #3 (Eliminate Possibilities) is needed at the end, because squaring an equation can invent roots that do not solve the original — every root has to be tested back, and one of the two survivors is ruled out only by the condition m > 0.

1STEP 1

Set up the picture and the unknowns

Write the line with two unknowns and translate each tangency.

ℓ : y = mx + b, P₁ = (2,4), r₁ = 4, P₂ = (14,9), r₂ = 9
2STEP 2

Tangent means distance equals radius

Tangency means the distance from a centre equals the radius.

ℓ is tangent to the circle (P, r) ⇔ dist(P, ℓ) = r
3STEP 3

Write that distance in coordinates

A signed distance records which side each centre is on.

d(x₀, y₀) = (mx₀ - y₀ + b)/(√(m²+1)), dist((x₀,y₀), ℓ) = |d(x₀,y₀)|
4STEP 4

"External" is a statement about signs

Same side means a shared sign, removing the absolute values.

(2m - 4 + b)/(√(m²+1)) = 4ε, (14m - 9 + b)/(√(m²+1)) = 9ε, ε ∈ {+1, -1}
5STEP 5

Subtract to eliminate b

Subtracting the two conditions eliminates the intercept.

(12m - 5)/(√(m²+1)) = 5ε
6STEP 6

Solve for the slope, then test the roots

Two roots appear and both are genuine, but only one has positive slope.

119m² = 120m → m = 0 or m = 120/119; m > 0 → m = 120/119, ε = +1
7STEP 7

Put the slope back to get b

Substituting back gives 912/119, choice (E).

b = 676/119 - 240/119 + 476/119 = 912/119 → (E)
Answer
912/119
The final line was verified directly against both circles, not just the one used to solve: the distances came out to exactly 4 and 9, with both signed distances positive, so both centers sit on the same side and the line really is a common external tangent. The arithmetic also has a fingerprint that says it is right — 119, 120, 169 is a Pythagorean triple, which is why √(m²+1) collapsed to the clean 169/119 instead of an ugly surd. Size check: b = 912/119 ≈ 7.66, and the picture shows the tangent crossing the y-axis a bit below the top of the small circle at y = 8, which matches. Note how tight the choices are: rewritten over the common denominator 119 they are 908/119, 909/119, 910/119, 911/119, 912/119 — five consecutive numerators, spanning only 4/119 ≈ 0.034 in total. No estimate or decimal shortcut can separate them, so the answer has to come from exact fractions carried the whole way. That is the real trap in this problem.
💡Key takeaway

"Tangent" means the distance from the center to the line equals the radius, and "external" means both centers land on the same side of the line — write those two facts as equations, subtract them to make b disappear, and the slope 120/119 falls out and hands you b = 912/119.

  • Set up the picture and the unknowns
  • Tangent means distance equals radius
  • Write that distance in coordinates
  • "External" is a statement about signs
  • Subtract to eliminate b
  • Solve for the slope, then test the roots
  • Put the slope back to get b