AMC 10 · 2007 · #10

Grade 6 algebra
percentagelinear-equations-one-var convert-to-algebra ↑ Prerequisites: percentage
📏 Short solution 💡 2 insights
Problem
A group starts at 40 percent girls, then two girls leave and two boys arrive. The mix becomes 30 percent girls. Find how many girls there were at the start.

Pick an answer.

(A)
4
(B)
6
(C)
8
(D)
10
(E)
12
How to solve
Strategy Convert to Algebra

The trick is that the total head count never changes, so it is the natural quantity to name. Introduce a variable for the total (Tool #4), then translate the two percent facts into expressions for the girl count before and after (Tool #13). Because a swap of two-for-two changes the girls by 2 but not the total, one clean equation pops out and solves in a line. Tool #3 (Eliminate Possibilities) is kept in reserve to sanity-check the result against the five answer choices.

1STEP 1

Name the total and the girls

The swap leaves the total unchanged.

total=n, girls=0.4n
2STEP 2

Translate the after-swap fact

So the after-picture is one equation in that total.

0.4n-2=0.3n
3STEP 3

Solve and read off the girls

Solving and taking the fraction gives 8, choice (B).

0.1n=2→ n=20, girls=0.4 × 20=8
Answer
8
Check the full story with 20 people and 8 girls. At the start, 8 of 20 is 8/20=40% girls, matching the first fact. After two girls leave and two boys arrive, there are 6 girls out of the same 20 people, and 6/20=30%, matching the second fact. Both conditions hold, so 8 girls is correct.
💡Key takeaway

When a swap keeps the total the same, name that total, write the girl count two ways, and set them equal.

  • Name the total and the girls
  • Translate the after-swap fact
  • Solve and read off the girls