AMC 10 · 2007 · #8
Grade 8 algebraPick an answer.
The problem already hands us two letters, T and N, so naming the remaining quantities in terms of them (Tool #4) is the natural move. The key that this tool unlocks is that 'N years ago' shifts each of the three children back by N, so their combined age drops by 3N, not by N. Once every age is written in T and N, the single sentence 'Tom's age then was twice their sum then' becomes one equation (Tool #13, Convert to Algebra), which we solve for the ratio T/N.
Write every age in terms of T and N
The children's total drops three times as fast going back.
Three kids each go back N years, so their ages together drop by 3N, three times as fast as one person's.
Three children each going back the same number of years drops their combined age three times as fast.
▸ Why?
The same step repeated once per child is a count of equal groups, which multiplying records.
▸ Why?
Everyone is shifted by the same amount, so the gaps between the ages are exactly what they were.
Turn the sentence into an equation
The past sentence becomes one equation.
'Was twice' means one side equals two copies of the other, which is exactly an equals sign with a factor of 2.
7.EE.A.1Convert To AlgebraSolve for the ratio T/N
Solving gives the ratio 5, choice (D).
Gathering the T's and N's onto opposite sides leaves a clean relationship between the two, which is all a ratio needs.
8.EE.C.7Introduce A VariableWhen you rewind time in an age problem, every person loses those years, so three children lose three times as many — count all of them before writing the equation.
- Write every age in terms of T and N
- Turn the sentence into an equation
- Solve for the ratio T/N