AMC 10 · 2008 · #6

Grade 7 algebra
percentagelinear-equations-one-var convert-to-algebra ↑ Prerequisites: percentagelinear-equations-one-var
📏 Medium solution 💡 1 insight
Problem
One store takes a smaller percent off and then a fixed rebate, another takes a larger percent off with no rebate. The first store's price is lower by a known amount. Find the sticker price.

Pick an answer.

(A)
750
(B)
900
(C)
1000
(D)
1050
(E)
1500
How to solve
Strategy Introduce a Variable

The one number we do not know is the sticker price, so the natural first move is Tool #4: call it S and write both store prices in terms of S. "15% off" means you still pay 85%, so store A costs 0.85S - 90; "25% off" means you pay 75%, so store B costs 0.75S. Tool #13 then turns the sentence "store A saves 15" into a single equation, and Tool #8 keeps every term in dollars so the flat90 rebate and the percent-based discounts can be added and subtracted safely.

1STEP 1

Name the sticker price

Naming the sticker price writes both stores with one letter.

S = sticker price (dollars)
2STEP 2

Turn percents into prices

A percent off is a multiplication, and the rebate a plain subtraction.

Store A = 0.85S - 90, Store B = 0.75S
3STEP 3

Write the savings equation

The stated saving becomes one equation.

Store B - Store A = 15 → 0.75S - (0.85S - 90) = 15
4STEP 4

Solve for the sticker price

Solving gives 750, choice (A).

0.75S - 0.85S + 90 = 15 → -0.10S + 90 = 15 → -0.10S = -75 → S = 750 → (A)
Answer
750
Plug S = 750 back in. Store A: 0.85 · 750 - 90 = 637.50 - 90 = 547.50. Store B: 0.75 · 750 = 562.50. The difference is 562.50 - 547.50 = 15, exactly the promised savings, and store A is indeed the cheaper one. So (A) 750 checks out.
💡Key takeaway

Turn "percent off" into "percent you pay," name the unknown price, and one clean equation from the savings clue hands you the sticker price.

  • Name the sticker price
  • Turn percents into prices
  • Write the savings equation
  • Solve for the sticker price