AMC 10 · 2008 · #16
Grade 7 geometry-2dnumber-theoryPick an answer.
The wording hides a clean equation. A quick sketch shows the 1-foot border shaves 2 feet off the width and 2 feet off the length, so the painted rectangle is (a-2) by (b-2). The 'half the area' condition then becomes an equation in a and b; rearranged and factored it turns into a product of two integers equal to 8. Counting the valid pairs is just listing the factor pairs of 8 and keeping the ones with b > a.
Sketch the border, size the inner rectangle
The border takes two units off each dimension.
A border of width 1 on both opposite sides eats 2 units off that whole dimension.
A border of width one on both opposite sides eats two units off that whole dimension.
▸ Why?
The floor is the border plus the painted middle, so the middle is the whole with the border removed.
▸ Why?
The same width is taken off each end, so both sides shrink equally and the shape stays a rectangle.
Turn 'half the area' into an equation
Half the area becomes one equation.
If the border is exactly half, the paint is the other half, so their two areas must be equal.
7.EE.B.4Convert To AlgebraExpand, then factor with the +16 trick
Adding a constant makes it factor into two brackets.
Adding just the right constant lets a stubborn two-variable expression collapse into a single neat product.
7.EE.A.1Convert To AlgebraList the factor pairs, keep b > a
Listing factor pairs and keeping the order gives 2, choice (B).
Every way to split 8 into two whole-number factors is one candidate floor, and the rule b > a discards the mirror-image pairs.
4.OA.B.4Make A Systematic ListA one-foot border shrinks each side by two; write the half-area rule as an equation, nudge it into a neat product, and count the factor pairs.
- Sketch the border, size the inner rectangle
- Turn 'half the area' into an equation
- Expand, then factor with the +16 trick
- List the factor pairs, keep b > a