AMC 10 · 2009 · #10

Grade 7 geometry-2d
polygon-inequalityinterval-arithmetic bound-inequality-then-enumerate ↑ Prerequisites: interval-arithmetic
📏 Medium solution 💡 2 insights 📊 Diagram
Problem
A quadrilateral has four known sides and one diagonal of whole-number length. Find that diagonal.

Pick an answer.

(A)
11
(B)
12
(C)
13
(D)
14
(E)
15
How to solve
Strategy Extreme Principle

The diagonal BD belongs to two different triangles at once, so Tool #7 (Identify Subproblems) splits the four-sided figure into △ BCD (sides 17, 5, BD) and △ ABD (sides 5, 9, BD). Inside each triangle the third side cannot be so long or so short that the other two fail to close up — that boundary is exactly the triangle inequality, so Tool #14 (Extreme Principle) pushes each triangle to its flat, zero-area edge to read off how big and how small BD is allowed to be. Those two boundaries trap BD inside a narrow band, and Tool #3 (Eliminate Possibilities) uses the whole-number clue to pick the single integer that survives.

1STEP 1

Cut the quadrilateral into two triangles

The diagonal cuts the shape into two triangles.

△ BCD: 17, 5, BD △ ABD: 5, 9, BD
2STEP 2

Lower bound from the big triangle

The larger triangle gives a lower bound.

BD + 5 > 17 → BD > 12
3STEP 3

Upper bound from the small triangle

The smaller gives an upper bound.

BD < 5 + 9 = 14
4STEP 4

Trap the integer

The whole-number condition traps it at 13, choice (C).

12 < BD < 14, BDinZ → BD = 13 → (C)
Answer
13
Check both triangles with BD=13. In △ BCD the sides 5,13,17 satisfy 5+13=18 > 17, a valid triangle. In △ ABD the sides 5,9,13 satisfy 5+9=14 > 13, also valid. Both hold with a little room to spare, and no other integer works: 12 fails (5+12=17, flat) and 14 fails (5+9=14, flat). So BD=13, matching (C).
💡Key takeaway

A diagonal cuts a quadrilateral into two triangles; make each triangle just barely close to trap the diagonal between two numbers, then the whole-number clue picks the winner.

  • Cut the quadrilateral into two triangles
  • Lower bound from the big triangle
  • Upper bound from the small triangle
  • Trap the integer