AMC 10 · 2009 · #22

Grade 10 geometry-3d
area-regular-hexagonsimilar-figurescoordinate-geometry spatial-visualizationidentify-subproblems ↑ Prerequisites: spatial-visualization
📏 Long solution 💡 4 insights
Problem
A plane parallel to a pair of opposite faces slices a regular octahedron into two congruent solids. Find the sum of the numbers describing the cross-section's area.

Pick an answer.

(A)
10
(B)
11
(C)
12
(D)
13
(E)
14
How to solve
Strategy Visualize Spatial Relationships

Nothing here can be measured until the octahedron is held in a fixed frame, so the first move is to sit it on its three diagonals as coordinate axes. Then the eight faces become eight simple planes, and every plane parallel to a chosen face pair is described by one number. Two subproblems remain: pin that number down (the congruence condition does it, and it is the step most people skip), and then find the polygon. Once the corners of the polygon are located, the side lengths and the area are ordinary plane geometry.

1STEP 1

Put the octahedron on coordinate axes

Axes give the solid a clean description.

vertices (± s,0,0),(0,± s,0),(0,0,± s); edge=s√(2)=1; solid={|x|+|y|+|z| ≤ s}
2STEP 2

Write the family of parallel cuts

The parallel cuts form a one-parameter family.

Pi_k: x+y+z=k, -s < k < s
3STEP 3

Congruent pieces force the cut through the center

A point symmetry forces the cut through the centre.

Pi₀: x+y+z=0; (x,y,z)↦(-x,-y,-z) maps the solid to itself and swaps {x+y+z ≥ 0} and {x+y+z ≤ 0}
4STEP 4

Locate where the plane meets the surface

The plane meets the surface at six points.

M₁=(s/2,-s/2,0), M₂=(s/2,0,-s/2), M₃=(0,s/2,-s/2), M₄=(-s/2,s/2,0), M₅=(-s/2,0,s/2), M₆=(0,-s/2,s/2)
5STEP 5

Every side is half an edge

Every resulting side is half an edge.

|M₁M₂|=|(0,s/2,-s/2)|=s/√(2)=s√(2)/2=1/2
6STEP 6

Show the hexagon is regular

Equal distances to the centre make it regular.

|OM_i|=√((s/2)²+(s/2)²)=s/√(2)=1/2; 6 × 60°=360°
7STEP 7

Compute the area of the hexagon

Its area follows from the standard formula.

[hexagon]=6·√(3)/4(1/2)²=6·√(3)/16=3√(3)/8
8STEP 8

Match the required form and add

Matching the required form and adding gives 14, choice (E).

3√(3)/8=a√(b)/c→ a=3, b=3, c=8; gcd(3,8)=1; a+b+c=14
Answer
14
Numerically three root 3 over 8 is about 0.650. A face has area root 3 over 4, about 0.433, and the largest flat slice through the center is one of the three square equators, of side 1 and area 1, so a middle cross-section between 0.433 and 1 is the right size. An independent recomputation confirms the number: drop the hexagon straight down onto the xy-plane. Its shadow has corners at plus or minus (half s, negative half s), (half s, 0), (0, half s), and so on, and the shoelace formula gives shadow area 3 times s squared over 4, which is 3 over 8 since s squared is one half. The cutting plane has unit normal (1,1,1) over root 3, so it is tilted from the xy-plane by an angle with cosine 1 over root 3, and a shadow shrinks area by exactly that cosine. So the true area is 3 over 8 divided by 1 over root 3, which is three root 3 over 8, matching the answer 14, choice (E). One more consistency check: the corners came out at distance one half from the center, which is the standard midsphere radius (half an edge) of a regular octahedron with edge 1.
💡Key takeaway

Stand the octahedron on its three diagonals, let the word congruent tell you the cut goes through the center, and the slice becomes a regular hexagon whose side is half an edge.

  • Put the octahedron on coordinate axes
  • Write the family of parallel cuts
  • Congruent pieces force the cut through the center
  • Locate where the plane meets the surface
  • Every side is half an edge
  • Show the hexagon is regular
  • Compute the area of the hexagon
  • Match the required form and add