AMC 10 · 2011 · #5

Grade 6 rate-ratio
percentageratio-proportionconditional-probability complementary-counting ↑ Prerequisites: percentage
📏 Medium solution 💡 2 insights
Problem
Four shares of a flock are known, and one kind is then removed from consideration. Find one kind's share of the rest.

Pick an answer.

(A)
20
(B)
30
(C)
40
(D)
50
(E)
60
How to solve
Strategy Change Focus / Count the Complement

The trap is that the 30% for geese is measured against ALL birds, but the question wants a percent measured against only the non-swan birds. So the real move is to change what counts as the whole. The non-swan birds are the complement of the swans, which is quick to find by subtracting. Pretending there are exactly 100 birds turns every percent into a plain count, so the final division is easy.

1STEP 1

Notice the whole changes

The whole being measured against has changed.

2STEP 2

Find the non-swan share

What remains is 75 percent of the flock.

100% - 25% = 75%
3STEP 3

Use 100 birds to make it concrete

Taking a hundred birds makes it concrete.

geese = 30, non-swans = 75
4STEP 4

Compare geese to the non-swans

Comparing gives 40 percent, choice (C).

30/75 = 2/5 = 0.4 = 40%
Answer
40
Removing the swans shrinks the whole from 100 to 75 while the 30 geese stay, so the geese must take up a bigger share than their original 30%. The answer 40% is indeed larger than 30%, which rules out 20% (A) and 30% (B). As a further check, the other non-swan groups give herons 10/75 ≈ 13% and ducks 35/75 ≈ 47%, and 40 + 13 + 47 rounds to 100%, so the non-swan shares add up correctly. That confirms choice (C).
💡Key takeaway

When a percent is 'out of' a smaller group, first find that group, then compare against it, not against everything.

  • Notice the whole changes
  • Find the non-swan share
  • Use 100 birds to make it concrete
  • Compare geese to the non-swans